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matrenka [14]
1 year ago
8

Solve each system by substitution. Check your answers. 4x+2y=7 , y = 5x

Mathematics
1 answer:
Kazeer [188]1 year ago
5 0

By substitution, the solution of the system of equations, 4x + 2y = 7 and y = 5x, is (1/2 , 5/2).

A system of linear equations is a set of two or more equations which includes common variables. To solve system of equations, we must find the value of the unknown variables used in the equations that must satisfy both equations.

There are three methods that can be used to solve system of linear equations.

1. Elimination

2. Substitution

3. Graphing

Using substitution method, given two linear equations in x and y,

4x + 2y = 7     (equation 1)

y = 5x     (equation 2)

Since the second equation is already expressed in y in terms of x, substitute the second equation to the first equation.

4x + 2y = 7     (equation 1)

4x + 2(5x) = 7

4x + 10x = 7

Combining all terms containing the variable x on one side and the constants on the other side of the equality, and solving for x.

4x + 10x = 7

14x = 7

x = 1/2

Substitute the value of x in the second equation and solve for y.

y = 5x

y = 5(1/2)

y = 5/2

Hence, the solution of the given system of equations is (1/2 , 5/2).

To learn more about solving systems of equations: brainly.com/question/25869125

#SPJ4

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2.5(12.75x + 24.50) = 188.75
mrs_skeptik [129]

Answer:

Step-by-step explanation:

First, in order to get rid of the parenthesis, you need to multiply 2.5 with whatever is in the parenthesis.

Multiply 2.5 on each side of the equation like this:

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Once you're finished, you should get 61.25 and 31.875x =188.75

Now in order to find 'x' you will need to subtract 61.25 to each side of the equation like this:

61.25 - 61.25 = 0

188.75 - 61.25 = 127.5

So now your equation should look like this:

31.875x = 127.5

You have to divide 31.875 by each side now.

Once you divide them, your final answer should be 4.

so x = 4.

I really hope this helps! ^^

5 0
2 years ago
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Answer:

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Step-by-step explanation:

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What lowest terms 19/31
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