All categories

3 years ago

2x+7=3x-5. Someone tell me

Mathematics

1 answer:

Naya [18.7K]3 years ago

8 0

Answer:

x ≥ 12

Step-by-step explanation:

You might be interested in

What is the value of 3x^2+4x+12 when x=-2

irina [24]

56 is the answer to the equation

3 0

3 years ago

Read 2 more answers

Which choice models this situation? Fahad needs to sell 25 tickets to a fundraiser by Friday. So far, he has sold 9 tickets. How

MrRa [10]

Answer:

16 tickets

Step-by-step explanation:

Number of tickets he has to sell = 25

Number of tickets he has sold = 9

How many tickets does he still need to sell?

Number of tickets he still needs to sell = Number of tickets he has to sell - Number of tickets he has sold

= 25 - 9

= 16 tickets

Number of tickets he still needs to sell = 16 tickets

Therefore, Fahad still needs to sell 16 more tickets

5 0

3 years ago

HELP! I WILL MARK BRAINLIEST!

jekas [21]

Answer:

Step-by-step explanation:

it is A

6 0

3 years ago

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago

Eric bought apples and oranges for $7.75. He paid $2.35 for all the apples

Kruka [31]

Answer:

He bought 12 oranges.

Step-by-step explanation:

Key words: "ALL the apples" "EACH orange."

7.75-2.35= 5.4

5.4/0.45= 12

8 0

3 years ago

2x+7=3x-5. Someone tell me​

2x+7=3x-5. Someone tell me