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Nitella [24]
1 year ago
7

Is running with a box work?

Physics
1 answer:
Harman [31]1 year ago
4 0
A major component of a good running stride is generating power from the hips to propel you forward – getting air and then landing again with a quick rebound to do it again and again. Box running is an ideal training aid for any runner, helping to build proper form, core strength and conditioning.
Hope this helps.
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The day VFR visibility and cloud clearance requirements to operate over the town of Cooperstown, after departing and climbing ou
pshichka [43]

Answer:

The correct option is;

C. 1 mile clear of clouds

Explanation:

Given that the indicated airspace location is at or below 700 feet AGL therefore, it is taken as being in the region of a class G airspace which covers the airspace regions from the base up to and equal to 1,200 feet beneath the class E airspace and the requirement for VFR flight for class G are 1 mile and clear of clouds.

4 0
3 years ago
How can different objects interact when they are not even touching?
jeka94

Answer: Magnetic and gravitational force

Explanation: When a magnet and an iron nail are kept at a distance,the magnet attracts the nail without touching using magnetic force. In this example, the magnet and the nail are interacting.

The earth pulls the moon towards it and keeps it in orbit without touching it, using gravitational force. In this example,the moon and the earth are interacting.

PLEASE RATE 5 STARS AND VOTE AS BRAINLIEST:)

(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)

3 0
3 years ago
A spacecraft is on a journey to the moon. At what point, as measured from the center of the earth, does the gravitational force
Alexeev081 [22]

Answer:

This distance is measured from the center of the earth   r = 3.4 10⁸ m

Explanation:

The equation for gravitational attraction force is

      F = G m1 m2 / r²

Where g is the universal gravitation constant, m are the masses of the body and r is the distance between them, remember that this force is always attractive

Let's write the sum of force on the ship and place the condition that is balanced

    F1 -F2 = 0

    F1 = F2

Let's write this equation for our case

   G m Me / r² = G m Mm / (r'.)²

   

The distance r is measured from the center of the earth and the distance r' is measured from the center of the moon,

   

      r' = 3.85 10⁸ m

Let's simplify and calculate the distance

     Me / r² = Mm / / (3.85 108- r)²

     Me / Mm (3.85 108- r)² = r²

     √ 81.4 (3.85 108 -r) = r

     √ 81.4  3.85 108 = r (1 + √ 81.4)

     34.74 108 = r (10.02)

     r = 34.74 10⁸ / 10.2

     r = 3.4 10⁸ m

This distance is measured from the center of the earth

6 0
4 years ago
Give an example of a situation in which you would describe an object's position in
notka56 [123]
Incomplete question.  Full text is:

"<span>Give an example of a situation in which you would describe an object's position in (a) one-dimension coordinates (b) two-dimension coordinates (c) three-dimension coordinates"

Solution
(a) One dimension example: a man walking along a metal plank. We just need to specify one coordinate, the distance from the beginning of the plank.

(b) Two-dimension example: a ball moving on a circle. In this case, we need two coordinates: (x,y) to specify the position of the ball at every instant, since it is moving on a 2-D plane.

(c) The position of an airplane in the air: in this case we need 3 coordinates, the height, the latitude and the longitude of the airplane.</span>
8 0
3 years ago
Spheres of Charge: A metal sphere of radius 10 cm carries an excess charge of +2.0 μC. What is the magnitude of the electric fie
nadezda [96]

To solve this problem we will apply the concept related to the electric field.  The magnitude of each electric force with which a pair of determined charges at rest interacts has a relationship directly proportional to the product of the magnitude of both, but inversely proportional to the square of the segment that exists between them. Mathematically can be expressed as,

E = \frac{kV}{r^2}

Here,

k = Coulomb's constant

V = Voltage

r = Distance

Replacing we have

E = \frac{(9*10^9)(2*10^{-6})}{((10+5)*10^{-2})^2}

E = 8*10^5N/C

Therefore the magnitude of the electric field is 8*10^5N/C

4 0
3 years ago
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