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mihalych1998 [28]
3 years ago
6

What factor determines an object's momentum?

Physics
1 answer:
vlada-n [284]3 years ago
3 0

Momentum = mass x velocity

So both mass and velocity affect an object's momentum.

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An electron is confined in a harmonic oscillator potential well. What is the longest wavelength of light that the electron can a
kipiarov [429]

Answer:

The longest wavelength of light is 209 nm.

Explanation:

Given that,

Spring constant = 74 N/m

Mass of electron m= 9.11\times10^{-31}\ kg

Speed of light c= 3\times10^{8}\ m/s

We need to calculate the frequency

Using formula of frequency

f =\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

Where, k= spring constant

m = mass of the particle

Put the value into the formula

f=\dfrac{1}{2\pi}\sqrt{\dfrac{74}{9.11\times10^{-31}}}

f=1.434\times10^{15}\ Hz

We need to calculate the longest wavelength that the electron  can absorb

\lambda=\dfrac{c}{f}

Where, c = speed of light

f = frequency

Put the value into the formula

\lambda =\dfrac{3\times10^{8}}{1.434\times10^{15}}

\lambda=2.092\times10^{-7}\ m

\lambda=209\ nm

Hence, The longest wavelength of light is 209 nm.

6 0
3 years ago
A spring that is stretched by hanging a 5kg mass. It's equilibrium length was 0.5 meters. Now the length of the spring is 1.6 me
gtnhenbr [62]
45 N/m as attached, please comment

5 0
3 years ago
A 5.0 kg box is sliding across a waxed floor by the application of a 15 N east force. If the force of friction is 2.5 N west, wh
coldgirl [10]

1) 12.5 N east

There are two forces acting on the box along the horizontal direction:

- The applied force of 15 N east, we indicate it with F

- The force of friction of 2.5 N west, we indicate it with F_f

Taking east as positive direction, we can write the two forces has

F=+15 N\\F_f = -2.5 N

Therefore, the net force on the box will be:

F_{net} = F + F_f = 15 + (-2.5) = +12.5 N

And the positive sign means the direction is east.

2) 2.5 m/s^2

We can solve this part by using Newton's second law:

F_{net}=ma

where

F_{net} is the net force on the box

m is its mass

a is the acceleration

For the box in this problem,

F_{net} = 12.5 m/s^2 (east)

m = 5.0 kg

Solving for a, we find the acceleration:

a=\frac{F_{net}}{m}=\frac{12.5}{5.0}=2.5 m/s^2

And the direction is the same as the net force (east)

6 0
3 years ago
An object is in motion when its distance from a(n) (what is in the blank?) is changing.
Ratling [72]
<span>An object is in motion when its distance from its point of origin is changing.</span>
3 0
3 years ago
A speed bike tops a hill at 3.50 m/s and accelerates steadily down the hill until reaching a speed of 11.4 m/s after 4.20 second
k0ka [10]

Answer:

The bike traveled 31.3 meters during this period

Explanation:

A speed bike tops a hill at 3.50 m/s and accelerates steadily down the

hill until reaching a speed of 11.4 m/s after 4.20 seconds

→ The initial speed u = 3.5 m/s

→ The final speed v = 11.4 m/s

→ The time of acceleration t = 4.2 seconds

→ a = \frac{v-u}{t}

Substitute the values above in the rule to find the acceleration a

→ a = \frac{11.4-3.5}{4.2} = 1.88 m/s²

We need to find the distance that the bike traveled during the

acceleration

→ v² = u² + 2 a s, where s is the distance

→ (11.4)² = (3.5)² + 2 (1.88)(s)

→ 129.96 = 12.25 + 3.76 s

Subtract 12.25 from both sides

→ 117.71 = 3.76 s

Divide both sides by 3.76

→ s = 31.3 meters

<em>The bike traveled 31.3 meters during this period</em>

8 0
3 years ago
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