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Volgvan
1 year ago
8

I really need help, fast. Please?

Mathematics
1 answer:
torisob [31]1 year ago
3 0

The slope of the line as shown in the graph attached is 7/3

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

A variable can either be independent or dependent. A dependent variable depends on other variable while an independent variable does not depend on other variable.

A linear equation is in the form:

y = mx + b

Where m is the rate of change (slope) and b is the y intercept.

The slope of a line = vertical rise / horizontal run

From the image:

Slope = rise / run = 7/3

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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What is the average rate of change for this exponential function for the
harina [27]

it is two i think. hope i could help

7 0
3 years ago
Giving 40 Points...need help as soon as possible
PIT_PIT [208]
The <u>correct answers</u> are:

The <span><u>first system</u> </span>matches with (-4, 5);
The <u>second system</u> matches with (2, 2); 
The <u>third sys</u><span><u>tem</u> </span>matches with (-1, -3);
The <u>fourth system</u> matches with (3, 4);
The <u>fifth system</u> matches with (2, -1); and 
<span>The <u>sixth system</u> matches with (-5, 6).</span>

<span>Explanation:</span>

The <u>sixth system</u> is the easiest one to find.  We are given the value of x and the value of y in the equations: x=-5 and y=6.

For all other systems, we must solve the system.  For the <u>first system</u>:
\left \{ {{2x-y=-13} \atop {y=x+9}} \right.

Since we have the y-variable isolated in the second equation, we will use substitution.  We substitute this value in place of y in the first equation:
2x-y=-13
2x-(x+9)=-13

Distributing the subtraction sign,
2x-x-9=-13

Combining like terms:
x-9=-13

Add 9 to each side:
x-9+9=-13+9
x=-4

Substitute this into the second equation:
y=x+9
y=-4+9
y=5

<u>The coordinates (-4, 5) represent the solution point.</u>

For the <u>second system</u>:
\left \{ {{3x+2y=10} \atop {6x-y=10}} \right.

We can make the coefficients of x the same and use elimination.  To do this, we will multiply the first equation by 2:
<span>\left \{ {{2(3x+2y=10)} \atop {6x-y=10}} \right. \\ \\ \left \{ {{6x+4y=20}  \atop {6x-y=10}} \right.

Since the coefficients of x are now the same, we can cancel it.  They are both positive, so we subtract:
\left \{ {{6x+4y=20} \atop {-(6x-y=10)}} \right. \\ \\5y=10

Divide both sides by 5:
5y/5=10/5
y=2

Substitute this into the second equation
6x-y=10
6x-2=10

Add 2 to each side:
6x-2+2=10+2
6x=12

Divide both sides by 6:
6x/6 = 12/6
x=2

<span><u>The coordinates (2, 2) represent the solution to this system.</u></span>

<span>For the <u>third system</u>:</span>
\left \{ {{4x-3y=5} \atop {3x+2y=-9}} \right.

We can make the coefficients of x the same by multiplying the first equation by 3 and the second by 4:
\left \{ {{3(4x-3y=5)} \atop {4(3x+2y=-9)}} \right. \\ \\ \left \{ {{12x-9y=15} \atop {12x+8y=-36}} \right.

Since the coefficients of x are the same, we can cancel them.  Since they are both positive, we will subtract:
\left \{ {{12x-9y=15} \atop {-(12x+8y=-36)}} \right. \\ \\-17y=51

Divide both sides by -17:
-17y/-17 = 51/-17
y=-3

Substitute this into the first equation:
4x-3y=5
4x-3(-3)=5
4x--9=5
4x+9=5

Subtract 9 from each side:
4x+9-9=5-9
4x=-4

Divide each side by 4:
4x/4 = -4/4
x=-1

<u>The coordinates (-1, -3) represent the solution of the third system..</u>

For the <u>fourth system</u>:
\left \{ {{x+y=7} \atop {x-y=-1}} \right.

Since the coordinates of x are the same and both are positive, we can cancel x by subtracting:
\left \{ {{x+y=7} \atop {-(x-y=-1)}} \right. \\ \\2y=8

Divide both sides by 2:
2y/2 = 8/2
y=4

Substitute this into the first equation
x+y=7
x+4=7

Subtract 4 from each side:
x+4-4=7-4
x=3

<u>The coordinates (3, 4) represent the solution to the fourth system.</u>

For the <u>fifth system</u>:
\left \{ {{y=3x-7} \atop {y=2x-5}} \right.

Since y is isolated in each equation, we can set them equation to each other:
3x-7=2x-5

Subtract 2x from each side:
3x-7-2x=2x-5-2x
x-7=-5

Add 7 to each side:
x-7+7=-5+7
x=2

Substitute this into the first equation:
y=3x-7
y=3(2)-7
y=6-7
y=-1

<span><u>The coordinates (2, -1) represent the solution to the fifth system.</u></span> </span>
7 0
3 years ago
Thank you guys for helping me I know I'm being annoying
Ierofanga [76]
A² + b² = c²

c² = 4² + 6.5²

c² = 58.25

c = 7.63

Perimeter = 4 + 6.5 + 7.63 = 18.13 units.

Perimeter after the increase in scale = 18.13 x 4 = 72.52 units.

Answer:  72.52 units
8 0
3 years ago
Solve for x parallel ​
umka2103 [35]

Answer:

x=5

Step-by-step explanation:

Hi there! So when it comes to these two angles, you have to set them equal to each other. From there, you have to isolate the x values, so I subtracted x from the 3x and added 15 to the -5. If you plug in the 5 for the x values, both give the value of 0, so it all checks out. I hope this helped! Please mark this as brainliest if I managed to get this correct. <3

8 0
3 years ago
What is the slope of the graph/ What does the slope tell you?<br><br> Answer both for brainliest
4vir4ik [10]

Answer:

Slope= 30

Step-by-step explanation:

What does the slope tell me?

It tells me that every time I try to find the slope with different points I get 30 for slope.

3 0
3 years ago
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