Question

a certain alcohol contains only three elements, carbon, hydrogen, and oxygen. combustion of a 50.00 gram sample of the alcohol produced 95.50 grams of co2 and 58.70 grams of h2o. what is the empirical formula of the alcohol?

Answer 1

Empirical formula is C2H6O

What is empirical formula?

While the molecular formula provides the precise quantity of each unique element present in a molecule, the empirical formula of a compound provides the simplest ratio of the number of various atoms present. It is an empirical formula if it has been simplified. The empirical formula is multiplied by the widely used molecular formula.

mass of CO2 = 76.4 g or after dividing by the molar mass 44 = 1.7360 moles of CO2 since there is 1 mole so C in CO2 = 1.7360 moles of C or 20.851 g of C which is the mass of C in the compound mass of H2O = 46.96 g or after dividing by the molar mass 18 = 2.6067 moles of H2O or since there are 2 moles of H in 1 moles of H2

molar ratio of C : H :O = 1.73598 : 5.2133 : 0.86843

or after dividing by the smallest 0.86843

molar ratio of C : H :O = 1.999 : 6.003 : 1.000

empirical formula is C2H6O

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