Answer:
what is the net ionic equation
H2SO4(aq) + Cal2(aq) → CaSO4(s) + 2Hl(aq)?
A. H++ SO42- + Ca2+ + 21 → CaSO4 + H+ +1-
B. 2H+ + S042- + Ca2+ + 21° → Ca2+ + SO42- + 2H+ + 21
C. S042- + Ca2+ → CaSO4,
D. 2H+ + SO42- + Ca2+ + 2I- → CaSO4 + 2H+ + 2I-
cancel the spectator ion that is the ions which does not take place in the reaction
for this case is 2 H^+ and 2 i^-
Halogens (atoms with 7 valence electrons) and Hydrogen
or generally, atoms with their shells almost full
Answer:6.94
Explanation:
Molar mass of CaCO3=40+12+16×3
=40+12+48=100g/mol
Moles=mass of substance/molar mass
=97mg/100g=0.097/100=0.00097moles/L.
PH=-log[CaCo3]=-log(0.00097)=6.94
P.s it's log to base e
