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dimaraw [331]
3 years ago
11

What is the molarity of a NaOH solution if 28.2 mL of a 0.355 M H2SO4 solution is required to neutralize a 25.0-mL sample of the

NaOH solution?A) 0.801B) 0.315C) 0.629D) 125E) 0.400
Chemistry
1 answer:
Anni [7]3 years ago
3 0

Answer:

A) 0.801

Explanation:

The reaction that takes place is:

  • 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

First we c<u>alculate the H₂SO₄ moles that reacted</u>:

  • 0.355 M * 28.2 mL = 10.011 mmol H₂SO₄

Now we <u>convert H₂SO₄ moles to NaOH moles</u>:

  • 10.011 mmol H₂SO₄ * \frac{2mmolNaOH}{1mmolH_2SO_4} = 20.022 mmol NaOH

Finally we <u>calculate the molarity of the NaOH solution</u>:

  • 20.022 mmol NaOH / 25.0 mL = 0.801 M

So the answer is option A.

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