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Zigmanuir [339]
2 years ago
14

Rewrite the rational exponent as a radical by extending the properties of integer exponents. 2 to the 3 over 4 power, all over 2

to the 1 over 2 power
Mathematics
1 answer:
Zepler [3.9K]2 years ago
6 0
We are asked in this problem to determine the simplified expression of the statement given. The rules that apply in exponential functions is that when an exponential term is raised to the power of an integer, the simplified term has a degree that is equal to the product of the integers involved. The operations involved should be applicable to terms with the same base number only.  In this problem, we thus write:

2^3/4 / 2^1/2 = 2^3/4 * 2^-1/2 = = 2^(3/4 - 1/2) = 2^ 1/4. hence the answer is 2^0.25 or simply equal to 1.1892 determined using a calculator.
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Darla budgeted $150 per week for food. Her actual monthly amount was an average of $700. Did Darla budget correctly?
mote1985 [20]
Yes she did :):):):):):)
6 0
2 years ago
"find the reduction formula for the integral" sin^n(18x)
dexar [7]
Let

I(n,a)=\displaystyle\int\sin^nax\,\mathrm dx
For demonstration on how to tackle this sort of problem, I'll only work through the case where n is odd. We can write

\displaystyle\int\sin^nax\,\mathrm dx=\int\sin^{n-2}ax\sin^2ax\,\mathrm dx=\int\sin^{n-2}ax(1-\cos^2ax)\,\mathrm dx
\implies I(n,a)=I(n-2,a)-\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx

For the remaining integral, we can integrate by parts, taking

u=\sin^{n-3}ax\implies\mathrm du=a(n-3)\sin^{n-4}ax\cos ax\,\mathrm dx\mathrm dv=\sin ax\cos^2ax\,\mathrm dx\implies v=-\dfrac1{3a}\cos^3ax

\implies\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx=-\dfrac1{3a}\sin^{n-3}ax\cos^3ax+\dfrac{a(n-3)}{3a}\int\sin^{n-4}ax\cos^4ax\,\mathrm dx

For this next integral, we rewrite the integrand

\sin^{n-4}ax\cos^4ax=\sin^{n-4}ax(1-\sin^2ax)^2=\sin^{n-4}ax-2\sin^{n-2}ax+\sin^nax
\implies\displaystyle\int\sin^{n-4}ax\cos^4ax\,\mathrm dx=I(n-4,a)-2I(n-2,a)+I(n,a)

So putting everything together, we found

I(n,a)=I(n-2,a)-\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx
I(n,a)=I(n-2,a)-\left(-\dfrac1{3a}\sin^{n-3}ax\cos^3ax+\dfrac{n-3}3\displaystyle\int\sin^{n-4}ax\cos^4ax\,\mathrm dx\right)
I(n,a)=I(n-2,a)-\dfrac{n-3}3\bigg(I(n-4,a)-2I(n-2,a)+I(n,a)\bigg)+\dfrac1{3a}\sin^{n-3}ax\cos^3ax
\dfrac n3I(n,a)=\dfrac{2n-3}3I(n-2,a)-\dfrac{n-3}3I(n-4,a)+\dfrac1{3a}\sin^{n-3}ax\cos^3ax

\implies I(n,a)=\dfrac{2n-3}nI(n-2,a)-\dfrac{n-3}nI(n-4,a)+\dfrac1{na}\sin^{n-3}ax\cos^3ax
7 0
2 years ago
Falling rock on another planet was detected as moving at the following speeds, corresponding to the time suggested in the table
Lady bird [3.3K]

Answer:

B. s = 24t

Step-by-step explanation:

Since s varies directly with t, therefore, equation that will represent the relationship would take the form of s = my

m = rate of change

✔️Find the rate of change:

Rate of change using two given pairs, (0.5, 12) and (2.5, 60),

Rate of change (m) = ∆s/∆t = (60 - 12)/(2.5 - 0.5) = 48/2 = 24

✔️Substitute m = 24 into s = mt

s = 24t

5 0
3 years ago
PLEASE HELP I WILL GIVE BRAINLY CROWN AND THIS QUESTION IS WORTH 62PTS
Thepotemich [5.8K]

Answer:

The y-intercept is 33ft.

Step-by-step explanation:

The ball is 33 feet away from the wall.

It will take the ball 11 seconds to touch the wall.

The slope is -3 feet. The ball is rolling towards the wall at 3 ft per second.

I hope this helps!

            ~Princess <3

3 0
2 years ago
Lucy rolls 2 fair dice and adds the results from each.
Daniel [21]

Answer:

Answer:

The probability of obtaining the sum of 10 is 1/12 or 0.0833

Step-by-step explanation:

Given

2 fair dice

Required

Probability of obtaining the sum of 10

To solve this, we have to list out the sample space.

Sample space is the total possible sum that can be obtained when she rolls the dice.

Let the first die be represented with S1 and the second be represented with S2.

S1 = {1,2,3,4,5,6}

S2 = {1,2,3,4,5,6}

To get the sample space, we have to add individual elements of S1 and S2.

This is done as follows.

When S1 = 1 and S2 = {1,2,3,4,5,6}

Sum = 1+1, 1+2, 1+3, 1+4, 1+5, 1+6

Sum = 2, 3, 4, 5, 6, 7

When S1 = 2 and S2 = {1,2,3,4,5,6}

Sum = 2+1, 2+2, 2+3, 2+4, 2+5, 2+6

Sum = 3,4,5,6,7,8

Using the same pattern as used above

When S1 = 3 and S2 = {1,2,3,4,5,6}

Sum = 4,5,6,7,8,9

When S1 = 4 and S2 = {1,2,3,4,5,6}

Sum = 5,6,7,8,9,10

When S1 = 5 and S2 = {1,2,3,4,5,6}

Sum = 6,7,8,9,10,11

When S1 = 6 and S2 = {1,2,3,4,5,6}

Sum = 7,8,9,10,11,12

Writing out the Sum, will give us the sample space.

Sample Space = {2, 3, 4, 5, 6, 7, 3, 4, 5, 6, 7, 8, 4, 5, 6, 7, 8, 9, 5, 6, 7, 8, 9, 10, 6, 7, 8, 9, 10, 11, 7, 8, 9, 10, 11, 12}

The sample space has a total of 36 elements

To calculate the probability of obtaining the sum of 10,

We have to count the number of 10's in the sample space

Number of 10 = 3

Probability = Number of 10 / Number of Sample Space

Probability = 3 / 36

Probability = 1/12

Probability = 0.0833

Hence, the probability of obtaining the sum of 10 is 1/12 or 0.0833

5 0
3 years ago
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