Answer:
Answer:
The probability of obtaining the sum of 10 is 1/12 or 0.0833
Step-by-step explanation:
Given
2 fair dice
Required
Probability of obtaining the sum of 10
To solve this, we have to list out the sample space.
Sample space is the total possible sum that can be obtained when she rolls the dice.
Let the first die be represented with S1 and the second be represented with S2.
S1 = {1,2,3,4,5,6}
S2 = {1,2,3,4,5,6}
To get the sample space, we have to add individual elements of S1 and S2.
This is done as follows.
When S1 = 1 and S2 = {1,2,3,4,5,6}
Sum = 1+1, 1+2, 1+3, 1+4, 1+5, 1+6
Sum = 2, 3, 4, 5, 6, 7
When S1 = 2 and S2 = {1,2,3,4,5,6}
Sum = 2+1, 2+2, 2+3, 2+4, 2+5, 2+6
Sum = 3,4,5,6,7,8
Using the same pattern as used above
When S1 = 3 and S2 = {1,2,3,4,5,6}
Sum = 4,5,6,7,8,9
When S1 = 4 and S2 = {1,2,3,4,5,6}
Sum = 5,6,7,8,9,10
When S1 = 5 and S2 = {1,2,3,4,5,6}
Sum = 6,7,8,9,10,11
When S1 = 6 and S2 = {1,2,3,4,5,6}
Sum = 7,8,9,10,11,12
Writing out the Sum, will give us the sample space.
Sample Space = {2, 3, 4, 5, 6, 7, 3, 4, 5, 6, 7, 8, 4, 5, 6, 7, 8, 9, 5, 6, 7, 8, 9, 10, 6, 7, 8, 9, 10, 11, 7, 8, 9, 10, 11, 12}
The sample space has a total of 36 elements
To calculate the probability of obtaining the sum of 10,
We have to count the number of 10's in the sample space
Number of 10 = 3
Probability = Number of 10 / Number of Sample Space
Probability = 3 / 36
Probability = 1/12
Probability = 0.0833
Hence, the probability of obtaining the sum of 10 is 1/12 or 0.0833
is odd. We can write
