Answer:
Step-by-step explanation:
With two congruent sides the third side is greater against a greater angle.
<u>34 < 36, therefore:</u>
<u>And, the angle should have a positive value:</u>
<u>Combined, we get:</u>
Answer:
<h2>30</h2>
Step-by-step explanation:
![3x+4y^2\\\\\text{Substitute the value of x = -2 and y = 3 to the expression:}\\\\3(-2)+4(3^2)\qquad\text{use PEMDAS}\\\\=-6+4(9)=-6+36=30](https://tex.z-dn.net/?f=3x%2B4y%5E2%5C%5C%5C%5C%5Ctext%7BSubstitute%20the%20value%20of%20x%20%3D%20-2%20and%20y%20%3D%203%20to%20the%20expression%3A%7D%5C%5C%5C%5C3%28-2%29%2B4%283%5E2%29%5Cqquad%5Ctext%7Buse%20PEMDAS%7D%5C%5C%5C%5C%3D-6%2B4%289%29%3D-6%2B36%3D30)
Answer:
no triangle can be formed with the given values (i.e 0 triangle).
Step-by-step explanation:
Given;
length of side a, = 10
length of side b, = 40
angle A, = 30°
Apply sine rule to determine the angle of the second side (B);
![\frac{sin \ A}{a} = \frac{sin \ B}{b} \\\\\frac{sin \ 30^0}{10} = \frac{sin \ B}{40}\\\\sin \ B = 40(\frac{0.5}{10} )\\\\sin \ B = 2](https://tex.z-dn.net/?f=%5Cfrac%7Bsin%20%5C%20A%7D%7Ba%7D%20%3D%20%5Cfrac%7Bsin%20%5C%20B%7D%7Bb%7D%20%5C%5C%5C%5C%5Cfrac%7Bsin%20%5C%2030%5E0%7D%7B10%7D%20%3D%20%5Cfrac%7Bsin%20%5C%20B%7D%7B40%7D%5C%5C%5C%5Csin%20%5C%20B%20%3D%2040%28%5Cfrac%7B0.5%7D%7B10%7D%20%29%5C%5C%5C%5Csin%20%5C%20B%20%3D%202)
The maximum sine function is 1, there is no sine function that will be equal to 2, so there is no triangle that can be formed with the given values.