Answer:
1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64
2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21
Step-by-step explanation:
1. Maximize: P = 4x +4y
Subject to: 2x + y ≤ 20
x + 2y ≤ 16
x, y ≥ 0
Plot the constraints and the objective function Z, or P=4x+4y)
Push the objective function to the limit permitted by the feasible region to find the maximum.
Answer: Objective function is a maximum at (16,0),
Z = 4x+4y = 4(16) + 4(0) = 64
2. Maximize P = 3x + 2y
Subject to x + y ≤ 8
2x + y ≤ 13
x ≥ 0, y ≥ 0
Plot the constraints and the objective function Z, or P=3x+2y.
Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.
Answer: Objective function is at a maximum at (5,3),
Z = 3x+2y = 3(5)+2(3) = 21
Answer:
eln2(x)ln(x4)/x
I HOPE THIS HELPED!
Step-by-step explanation:
Answer:
The number is 8.
Step-by-step explanation:
Write an equation then solve by isolating the variable.
let x be the number
4x + 15 = 47 Subtract 15 from both sides
4x = 47 - 15
4x = 32 Divide both sides by 4
x = 32/4
x = 8
Therefore the number is 8.
Answer:
136/2 = 68
Step-by-step explanation:
8 x 8 = 64 and
12 x 6 = 72
72 + 64 = 136
Answer:
The answer to your question is:
x = 1
Square's perimeter = 12
Rectangle perimeter = 12
The value of x is one and the perimeter of the square and the rectangle is the same.
Step-by-step explanation:
Data
Side of Square = 4x - 1
Length of rectangle = 2x + 1
Width = x + 2
Perimeters are the same
Process
Square perimeter = 4(4x - 1)
Rectangle's perimeter = 2(2x + 1) + 2(x+ 2)
Then
4(4x - 1) = 2(2x + 1) + 2(x+ 2) Equation
16x - 4 = 4x + 2 + 2x + 4
16x - 4 = 6x + 6
16x - 6x = 6 + 4
10x = 10
x = 10 / 10
x = 1
Perimeter of the square = 4(4(1) - 1)
= 4(3)
= 12
Perimeter of the rectangle = 2(2(1) + 1) + 2((1)+ 2)
= 2(3) + 2(3)
= 6 + 6
= 12