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Olin [163]
3 years ago
10

Help and explain please.

Mathematics
2 answers:
Over [174]3 years ago
7 0
I believe the answer would be 6.70820393 or ≈ 6.7 depending on how many decimal points you can put in.

So a^2+b^2 = c^2

In this case you are trying to find b

2^2+b^2 = 7^2
4 + b^2 = 49
B^2 = 45
b = the square root of 45

That is 6.70820393 or ≈ 6.7

Then see if it makes sense

2^2 + 6.7^2 = c^2

2(2) = 4
6.7(6.7) ≈ 45 (44.89)
———————-
49

And the square root of 49 is 7

Please correct me if I am wrong and have a good day
ruslelena [56]3 years ago
3 0

Answer:

  • a2 + b2 = c2
  • 4 + b2 = 49
  • b =
  • \sqrt{45}

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Dennis_Churaev [7]
" the product " means multiply

the product of 8 and a number Q is at least 32...

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4 years ago
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An object launched straight up at a speed of 29.4 meters per second has a height, h, in meters of h , t seconds after the object
Nostrana [21]

Answer:

h = 44.06 meters (maximum height)

the time the object takes to complete this whole path is 6 seconds, this is why the time at which the object reaches its maximum height will between 0 and 6 seconds

Step-by-step explanation:

To solve this question, we need to first recognize that this is a constant acceleration problem, specifically, it can be thought of as a projectile motion problem.

Recall, the equations of motion:

1) v^2 - v_0^2 = 2a(s - s_0)\\2) s = v_0^2  + \frac{1}{2} at^2\\3) v = v_0 + at

What do we already know?

  • v_0 = 29.4 ms^-1
  • The launch is straight up
  • a = -9.81 ms^-2 this is the gravitational acceleration g
  • s_0 = 0 m, since our reference point is at s = 0, (the ground)

We can use use the Eq(1):

we know that when any object is launched up, at maximum height its velocity is going to be zero, v = 0 ms^-2

v^2 - v_0^2 = 2a(s - s_0)\\0^2 - (29.4)^2 = 2(-9.81)(s- 0)\\s = 44.06 m

this is the maximum height!

Why does t have to between zero and six?

We can answer this using a bit visualization, if you think about the second equation

s = v_0 t - \frac{1}{2}at^2\\ s = 29.4t - 4.905t^2

this is the equation of the whole trajectory that object makes.

and if you solve this by making s = 0, you will get the times at which the object was at the ground. the times will be 0s and 5.99s.

so the amount of time the object takes to go through this whole path is 6 seconds and this why the object will only reach its maximum height in between this time interval.

hope this helps :)

5 0
3 years ago
If the fuel tank in Jim's car holds 14 gallons of fuel, define a formula to determine the number of gallons of fuel in Jim's fue
salantis [7]

Considering that the car does 50 miles per gallon, the linear function for the number of gallons of fuel in Jim's fuel tank, n, in terms of the number of miles x that Jim has driven since filling his tank is given by:

y = -0.02x + 14

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0.

In this problem:

  • Jim's car holds 14 gallons of fuel, hence b = 14.
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Hence, the function is:

y = -0.02x + 14

You can learn more about linear functions at brainly.com/question/25898120

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Answer:If we're solving for t my work is below:

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If we're solving for s my work is below:

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Step-by-step explanation:

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IRINA_888 [86]
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Hope this helps! :)
3 0
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