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2 years ago

If ∠1 and ∠2 are vertical angles and m∠2=108°, find m∠1.

Mathematics

1 answer:

marysya [2.9K]2 years ago

5 0

Answer:

Step-by-step explanation:

Is it 72???

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Find the number of terms for this polynomial.<br> 3

Natalka [10]

Answer:

Im sorry, im not in high school yet :(

Step-by-step explanation:

:( wish i could help :(

8 0

2 years ago

Someone please help me I’ve been trying all day!<br><br> NO LINKS , answers only <br> I MEAN IT!!!!

DedPeter [7]

Answer:

Step-by-step explanation:

You want to set up a system. We are given some points fo we can set up inputs and outputs. F(0) = 5, given by point (0,5). and F(3)=135, given by point (3,135). The exponential function general equation is F(x)= a(b)^x. plug in out functions into the general equation to get a(b)^0=5 and a(b)^3=135. Then you simplify and solve for a. In the equation a*b^0=5, anything to the power of 0 is 1. so a*1=5. Therefore a=5. we plug in the a to the second equation to find b. 5*b^3=135. b^3=27. b=3 from simplifying. Therefore, the equation should be 5(3)^x. THATS IT!

3 0

2 years ago

During bowling practice, Marley rolled 14 strikes out of 70 attempts.

Masja [62]

Answer:

20%

Step-by-step explanation:

to find out we make it a fraction:

14/70

then divide

14÷70=0.2

then times it by 100

= 20%

8 0

2 years ago

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Can anyone help me solve a trigonomic identity problem and also help me how to do it step by step?

dusya [7]

$\bf cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\qquad csc(\theta)=\cfrac{1}{sin(\theta)}
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\\\\
-------------------------------\\\\$

$\bf \cfrac{cos(\theta )cot(\theta )}{1-sin(\theta )}-1=csc(\theta )\\\\
-------------------------------\\\\
\cfrac{cos(\theta )\cdot \frac{cos(\theta )}{sin(\theta )}}{1-sin(\theta )}-1\implies \cfrac{\frac{cos^2(\theta )}{sin(\theta )}}{\frac{1-sin(\theta )}{1}}-1\implies 
\cfrac{cos^2(\theta )}{sin(\theta )}\cdot \cfrac{1}{1-sin(\theta )}-1
\\\\\\
\cfrac{cos^2(\theta )}{sin(\theta )[1-sin(\theta )]}-1\implies 
\cfrac{cos^2(\theta )-1[sin(\theta )[1-sin(\theta )]]}{sin(\theta )[1-sin(\theta )]}$

$\bf \cfrac{cos^2(\theta )-1[sin(\theta )-sin^2(\theta )]}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{cos^2(\theta )-sin(\theta )+sin^2(\theta )}{sin(\theta )[1-sin(\theta )]}
\\\\\\
\cfrac{cos^2(\theta )+sin^2(\theta )-sin(\theta )}{sin(\theta )[1-sin(\theta )]}\implies \cfrac{\underline{1-sin(\theta )}}{sin(\theta )\underline{[1-sin(\theta )]}}
\\\\\\
\cfrac{1}{sin(\theta )}\implies csc(\theta )$

7 0

2 years ago

HELP IM TIMED JUST ONE LAST QUESTION

Arturiano [62]

Answer:

Step-by-step explanation:

may I please have brainlyest

6 0

2 years ago

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