Hello everyone, need help on this, select all the correct answers that are equivalent.
1 answer:
9514 1404 393
Answer:
see attached
Step-by-step explanation:
You can perform the division and look at the quotient and remainder to convert an improper fraction to a mixed number.
23 ÷ 6 = 3 r 5 ⇒ 23/6 = 3 5/6 ≠ 4 1/6
11 ÷ 4 = 2 r 3 ⇒ 11/4 = 2 3/4 ≠ 2 1/2
35 ÷ 4 = 8 r 3 ⇒ 35/4 = 8 3/4
15 ÷ 8 = 1 r 7 ⇒ 15/8 = 1 7/8
40 ÷ 12 = 3 r 4 ⇒ 40/12 = 3 4/12 = 3 1/3
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Answer:
n=6
"=T.INV(1-0.025,5)", and we got the critical values given by:
n=12
"=T.INV(1-0.025,11)", and we got the critical values given by:
Step-by-step explanation:
Previous concepts
The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."
Solution to the problem
For n=6
In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking on the t distribution with df=n-1=6-1=5 degrees of freedom, a value that accumulates of the area on each tail. We can use excel or a table to find it, for example the code in Excel is:
"=T.INV(1-0.025,5)", and we got the critical values given by:
For n=12
In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking on the t distribution with df=n-1=12-1=11 degrees of freedom, a value that accumulates of the area on each tail. We can use excel or a table to find it, for example the code in Excel is:
"=T.INV(1-0.025,11)", and we got the critical values given by: