We are given: Function y=f(x).
First x-intercept of the y=f(x) is 2.
x-intercept is a point on x-axis, where y=0.
Replacing y by 0 and x by 2 in above function, we get
0=f(2)
Second x-intercept of the y=f(x) is 3.
Replacing y by 0 and x by 2 in above function, we get
0=f(3)
We are given another function y=8f(x).
Here only function f(x) is being multiplied with 8.
That is y values of function should be multiply by 8.
Because we have y value equals 0. On multiplying 8 by 0 gives 0 again and it would not effect the values of x's.
Therefore,
x-intercepts of y=8f(x) would remain same, that is 2 and 3.
Answer:
5 hours must pass
Step-by-step explanation:
Graph the equations y = 2x + 100 and y = -6x + 140
Then find the x intercept of their intersection, in this case, that is 5
95.7942857 pie form hope this is right got it off the internet so yeah
Answer:
$23.75
Step-by-step explanation:
divide $28.50 by 6 to find the price for 1 bag which is $4.75 then multiply $4.75 by 5 and that equals $23.75
This question is very oddly worded. The domain is the set of x-values, but this is a set of (x,y) ordered pairs.
I'm reading this question as "Here's a function, { (1,5), (2,1), (-1,-7) }. If this is reflected over the x-axis, what's the range?"
Assuming that is the question that is meant to be asked, reflecting a function over the x-axis will just change the signs of the y-values.
(1,5) -> (1,–5)
(2,1) -> (2,–1)
(-1,-7) -> (-1,+7)
I'd pick the third option.
