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polet [3.4K]
1 year ago
9

Using the quadratic formula, solve 0 = 2x² - 10x + 7 Give each of your answers to 2 d.p.

Mathematics
1 answer:
xenn [34]1 year ago
5 0

Answer:

\sf \: x =  \frac{5}{2}  +   \frac{ ± 1}{2} \sqrt{11}

Step-by-step explanation:

Let's solve your equation step-by-step.

0=2x²−10x+7

Step 1: Subtract 2x^2-10x+7 from both sides.

0−(2x²−10x+7)=2x²−10x+7−(2x²−10x+7)

−2x²+10x−7=0

For this equation: a=-2, b=10, c=-7

−2x²+10x+−7=0

Step 2: Use quadratic formula with a=-2, b=10, c=-7.

\sf \: x =  \frac{ - b ± \sqrt{ {b}^{2}  -  4ac }  }{2a}

\sf \: x =  \frac{ - (10)± \sqrt{ {10}^{2} - 4( - 2)( - 7) } }{2( - 2)}

\sf \: x =  \frac{ - 10 ± \sqrt{44}  }{ - 4}

\sf \: x =  \frac{5}{2}  +   \frac{ ± 1}{2} \sqrt{11}

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Answer:

Hi! The answer to your question is x = 7

Step-by-step explanation:

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Find the inverse of the following function. f(x) =^3squareroot x + 12<br><br> I NEED AN ANSWER NOWW
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Answer:

(x - 12)²/9

Step-by-step explanation:

y = 3sqr(x) + 12

Make x the subject:

y - 12 = 3sqrt(x)

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Square both sides

(y - 12)²/9 = x

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inverse function is:

(x - 12)²/9

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Then,

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Double a number decreased by 4
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A certain bay with very high tides displays the following behavior. In one 12-h period the water starts at mean sea level, rises
Firdavs [7]

Answer:

the required equation is; y = 21 sin(πt/6)

Step-by-step explanation:

Given the data in the question;

Water rises above sea level = 21 ft

Water drops below sea level = 21 ft

so

maximum = 21 ft and also

minimum = 21 ft

Amplitude = ( maximum + minimum ) / 2

Amplitude = ( 21 + 21 ) / 2

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Period = 12 hours

and we know that; period = 2π/b

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12 = 2π/b

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b = 2π / 12

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we substitute

y = 21 sin(πt/6)

Hence the required equation is; y = 21 sin(πt/6)

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The ages of armadillos are normally distributed, with a mean of 14 years and a standard deviation of 1.2. Approximately what per
vovangra [49]

Answer:

Percentage of armadillos between 13 and 17 years = 79.052%f using Standard Normal Distribution Tables

Step-by-step explanation:

As we know from normal distribution: z(x) = (x - Mu)/SD

where x = targeted value; Mu = Mean of Normal Distribution; SD = Standard Deviation of Normal Distribution

Therefore using given data: Mu = 14, SD = 1.2 we have z(x) by using z(x) = (x - Mu)/SD as under:

Approach 1 using Standard Normal Distribution Table:

z for x=17: z(17) = (17-14)/1.2 gives us z(17) = 2.5

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Afterwards using Normal Distribution Tables we find the probabilities as under:

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Finally in order to find out the probability between 17 & 13 years we have:

Percentage of armadillos between 13 and 17 years = P(17) - P(13) = 99.379% - 20.327% = 79.052%

The standard normal distribution table is being attached for yours easiness.

Approach 2 using Excel or Google Sheets:

P(17) = norm.dist(17,14,1.2,1)

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Percentage of armadillos between 13 and 17 years = { P(17) - P(13) } * 100

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