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denis23 [38]
3 years ago
11

X(x+1)(x+3)(x+5) - x(x+3)(x+5)

Mathematics
1 answer:
mash [69]3 years ago
8 0

Answer:

x^4 + 8x^3 + 15x^2

Step-by-step explanation:

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You solve an equation like this by adding the opposite of the constant to both sides of the equation.

... V -16 +16 = -32 +16 . . . . . addition property of equality: if a=c, then a+b = c+b

... V + 0 = -16 . . . . . . . . . . . . additive inverse property of integers: -16+16 = 0

... V = -16 . . . . . . . . . . . . . . . identity element of addition: V+0 = V

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<em>You can always do the same thing to both sides of an equation.</em> Here, it is useful to add the opposite of -16 to both sides. That way the constant on the left becomes zero, so you only have the variable by itself—which is what you want.

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Can we see an attachment of the problem?
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I hope it helps you

:-))

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