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Artemon [7]
1 year ago
5

How many gallons of water will be in the fish tank after 3 minutes?

Mathematics
1 answer:
enyata [817]1 year ago
4 0

If Mai is filling her fish tank with water flowing into the tank at a constant rate, and the tank fills 0.8 gallons in 0.5 minutes, then the tank will be filled with 4.8 gallons of water after 3 minutes.

As per the question statement, Mai is filling her fish tank with water flowing into the tank at a constant rate, and the tank fills 0.8 gallons in 0.5 minutes.

We are required to calculate the volume of water in gallons, that will be filled in the above mentioned tank after 3 minutes.

Here, it is given that, the tank gets filled with 0.8 gallons of water in 0.5 minutes, and that, the water flows into the tank at a constant rate.

So first, let us calculate the water flow rate into the tank per minute, that is, [(0.8 * 2) = 1.6 gallons] per minute, since [(0.5 minutes * 2) = 1 minute]

Therefore, the tank will get filled with [(1.6 * 3) = 4.8 gallons] of water in 3 minutes, if the water inflow rate is 1.6 gallons per minute.

  • Gallons: A gallon (gal) is a measuring unit for volume and capacity, typically used by the U.S. customary and earlier by the British Imperial Systems of Measurement, with 1 US gallon being equal to 3.785411784 Litres, and 1 imperial gallon being equal to 4.54609 L.

To learn more about Gallons and Constant Flow Rates, click on the link below.

brainly.com/question/17856253

#SPJ1

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Answer:

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Step-by-step explanation:

15ab-9a^2-6  \frac{1}{4} b^2 \\  \\  = 15ab-(3a)^2-\frac{6 \times 4 + 1}{4} b^2 \\  \\ = 15ab-(3a)^2-\frac{24+ 1}{4} b^2 \\  \\ = 15ab-(3a)^2-\frac{25}{4} b^2 \\  \\   = 15ab- (3a)^2- \bigg(\frac{5}{2} b \bigg)^2  \\  \\ =  -  \{ - 15ab + (3a)^2 +  \bigg(\frac{5}{2} b \bigg)^2  \} \\  \\ =  -  \{ (3a)^2 +  \bigg(\frac{5}{2} b \bigg)^2 - 15ab  \} \\  \\  =   - \bigg(3a -  \frac{5}{2} b \bigg)^{2}

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