All real numbers. Range is what y variable it could be.
Answer:
I think is: x = 344/23
Step-by-step explanation:
Answer:
Cost of 1 beef= $7.5
Cost of 1 bacon= $6
Step-by-step explanation:
Ok so first of organize everything:
We know she buys 6 pounds ->beef and 3 pounds ->bacon
First we need to set up an equation of how much 1 beef costs and 1 bacon costs:
Let’s say f=cost of 1 beef and b=cost of 1 bacon
Now lets make the equation:
6f+3b=63. (She buys 6 portions of beef and 3 bacon and her total comes out to 63)
Now their is another condition that the cost of one bacon is -$1.50 per pound than beef.
So we can say b=f-1.50
Do you notice anything similar? The b has a value now and so we can replace the b in our first equation with the b of the 2nd (b=b)
So hence,
6f+3(f-1.50)=63
6f+3f-4.5=63
9f=67.5
F=7.5 (This is the cost for 1 pound of beef)
Now lets find out for bacon,. Now instead of doing this equation all over again just insert it into the b=f-1.5 you know make life easier for yourself:
B=7.5-1.5
B=6
Cost of 1 beef= $7.5
Cost of 1 bacon= $6
Answer:
f(x+1) = -3/4 × f(x)
Step-by-step explanation:
first of all, the sign of the numbers in the sequence is alternating. so, there must be a "-" involved.
that eliminates the first and third answer options.
and the absolute values of the numbers in the sequence are going down. |f(x+1)| < |f(x)|
that eliminates the fourth answer option, as this says that
|f(x)| < |f(x+1)|. and that is the opposite of how the actual sequence behaves.
Answer: " 15 % " .
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→ " 12 is <u> 15% </u> of 80 " .
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Step-by-step explanation:
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12 = (n/100) * 80 ;
12 = (80n) /100 ; Solve for "n:
Note: 80/100 = (80/10) / (100/10) = (8/10) = 0.8 ;
12 = (0.8)n ;
↔ (0.8n) = 12
Multiply each side of the equation by "10" ; to get rid of the "decimal" ;
10 * (0.8n) = 10 * 12 ;
to get:
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8n = 120 ;
Divide each side of the equation by "8" ;
to isolate "n" on ONE SIDE of the equation; & to solve for "n" ;
8n/8 = 120/ 8 ;
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to get:
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n = 15 .
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Answer: " 15 % " .
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→ " 12 is <u> 15% </u> of 80 " .
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Hope this helps!
Best wishes!
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