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anastassius [24]
1 year ago
4

What happens when a magnet is moved back and forth inside a wire coil?A.Electric charges begin flowing through the wire.B.The ma

gnetic force decreases.C.Electric charges begin flowing through the magnet.D.The magnetic force increases.
Physics
1 answer:
AfilCa [17]1 year ago
6 0

According to electromagnetic induction, a change in the magnetic field induces a current in the circuit.

Thus, electric charges begin flowing through the wire when the magnet is moved back and forth inside a wire coil.

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At what net rate does heat radiate from a 300-m^2 black roof on a night when the roof's temperature is 33.0°C and the surroundin
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Answer:

24445.85 J/s

Explanation:

Area, A = 300 m^2

T = 33° C = 33 + 273 = 306 k

To = 18° C = 18 + 273 = 291 k

emissivity, e = 0.9

Use the Stefan's Boltzman law

E = \sigma  \times e \times A\times\left ( T^4 -T_{0}^{4}\right )

Where, e be the energy radiated per unit time, σ be the Stefan's constant, e be the emissivity, T be the temperature of the body and To be the absolute temperature of surroundings.

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E = 5.64 \times 10^{-8}\times 0.9 \times 300 \times  (306^{4}-291^{4})

E = 24445.85 J/s

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4 years ago
What is an oscillation on waves?
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Read 2 more answers
The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 o
shepuryov [24]

Complete Question

The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 ounces with a sample standard deviation of 0.5 ounces. At the 0.05 level of significance,perform a hypothesis test to see if the true mean weight is  less than 4 ounce.

Answer:

Yes the true mean weight is less than 4 ounce

Explanation:

  From the question we are told that

     The random sample is n = 15

       The mean weight is \= x = 3.8\  ounce

        The standard deviation is  \sigma = 0.5 \ ounce

         The  level of significance is  \alpha  = 0.05

       

So

   The  null hypothesis is  H_o : \mu \ge 4

     The alternative hypothesis is H_a : \mu < 4

Generally the critical value which a bench mark to ascertain whether the null hypothesis is  true or false is mathematically represented as

            t_{0.05} = 1.79

This value is  obtained from  the critical value table

Generally the test statistics is mathematically represented as

                Test \ Statistics (ST)  = \frac{\= x - \mu }{\frac{\sigma}{\sqrt{n} }  }

           =>  ST = \frac{3.8 -4 }{\frac{0.5}{\sqrt{20} } }

                ST = - 1.79

So since ST is less than t_{0.05}  then the null hypothesis would be rejected and the alternative hypothesis would be accepted so

  Thus the true mean weight is less than 4

4 0
3 years ago
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