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Rina8888 [55]
3 years ago
9

An infinitely long cylinder of radius R has linear charge density λ. The potential on the surface of the cylinder is V0, and the

electric field outside the cylinder is Er=λ2πϵ0r. Part A Find the potential relative to the surface at a point that is distance r from the axis, assuming r>R. Express your answer in terms of the variables λ, r, R, V0, and appropriate constants. Vr = nothing

Physics
1 answer:
tamaranim1 [39]3 years ago
5 0

Answer:

V = V_0 - (lamda)/(2pi(epsilon_0))*ln(R/r)

Explanation:

Attached is the full solution

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A charge of 24 C pass a certain point in a conductor in 10 s. What is the size of current in the conductor?
allsm [11]

Answer:

write the name of any five districts of nepal

6 0
2 years ago
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He vector parts that add up to the resultant are called ____.
cupoosta [38]

1. Answer: components

A two dimensional vector can be divided into two parts called horizontal component and vertical component.

A three dimensional vector can be divided into three components: one along x-axis, one along y-axis and one along z-axis.

Hence, the vector parts that add up to the resultant are called components.

2. Answer: 5 miles.

The resultant distance along the straight line from the starting point to the end point would be the displacement.

The displacement would be equal to the magnitude of the hypotenuse formed in the right triangle.

Displacement, d=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5 miles

3. Answer: Scalar

A scalar quantity has only magnitude. For example, speed and distance are scalar quantities and can be normally added to find the total.

A vector quantity has both magnitude as well as direction. The components are summed according to vector addition rules. For example, velocity, acceleration, force etc.

5 0
3 years ago
A block of ice at 0°C is added to a 150g aluminum calorimeter cup which holds 210 g of water at 12°C. If all but 2.0 g of ice me
Over [174]

Answer:

original mass of the block of ice is 38.34 gram

Explanation:

Given data

cup mass = 150 g

ice temperature = 0°C

water mass = 210 g

water temperature = 12°C

ice melt = 2 gram

to find out

solution

we know here

specific heat of aluminum is c = 0.900 joule/gram °C

Specific heat of water C =  4.186 joule/gram °C

so here temperature difference is dt =  12- 0 = 12°C

so here heat lost by water and cup are given by

heat lost  = cup mass × c  × dt + water  mass × C × dt

heat lost  = 150 × 0.900  × 12 + 210 × 4.186 × 12

heat lost  = 12168.72 J

so

mass of ice melt here = heat lost / latent heat of fusion

here we know latent heat of fusion = 334.88 joule/gram

so

mass of ice melt  =  12168.72 / 334.88

mass of ice melt  is 36.337554 gram

so mass of ice is here = mass of ice melt + ice melt

mass of ice  =  36.337554 + 2

mass of ice  =  38.337554 gram

so original mass of the block of ice is 38.34 gram

7 0
3 years ago
Five moles of an ideal monatomic gas with an initial temperature of 121 ∘C expand and, in the process, absorb an amount of heat
liq [111]

Answer:

  T₂ ≈ 107.85∘C

Explanation:

The question didn't state if the volume is constant or not as such, we can apply the first law of thermodynamic

From the first law of thermodynamic,

ΔU =  Q - W

where ΔU = Internal Energy, Q = Quantity of heat absorbed, W = Amount of work done.

Q = 1200 J and W = 2020 J

∴ ΔU = 1200 -2020 = -820 J.

Using the ideal gas equation,

ΔU = 3/2nRΔT...................................equation 1

where n = number of moles, R = Molar gas constant, ΔT = Change in temperature = (T₂ - T₁).

Modifying equation 1,

ΔU = 3/2nR(T₂ -T₁)...............................equation 2.

making T₂ the subject of the relation in equation 2,

T₂ =  {2/3(ΔU)/nR}+T₁........................ equation 3

where T₁=121∘C, R= 8.314 J / mol, n=5 moles, ΔU=-820 J

Substituting these values into equation 3,

∴ T₂ ={ 2/3(-820)/(5×8.314)}+121

   T₂ = {2×(-820)/ (3×5×8.314)}+121  

   T₂={-1640/124.71}+ 121

   T₂ = {-13.151} + 121

 ∴T₂  = 121 - 13.151 = 107. 849∘C

    T₂ ≈ 107.85∘C

3 0
3 years ago
Identify two size dependent properties and two size independent properties of an iron nail
Vedmedyk [2.9K]

2 size dependent = volume and mass. 2 size independent properties = conductivity, bowing point, state of matter, and melting point. analyze, name two size dependent properties and two size independent properties of an iron nail.


hope this helps

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