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Rina8888 [55]
3 years ago
9

An infinitely long cylinder of radius R has linear charge density λ. The potential on the surface of the cylinder is V0, and the

electric field outside the cylinder is Er=λ2πϵ0r. Part A Find the potential relative to the surface at a point that is distance r from the axis, assuming r>R. Express your answer in terms of the variables λ, r, R, V0, and appropriate constants. Vr = nothing

Physics
1 answer:
tamaranim1 [39]3 years ago
5 0

Answer:

V = V_0 - (lamda)/(2pi(epsilon_0))*ln(R/r)

Explanation:

Attached is the full solution

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A car is moving at 10 m/s to the right. It accelerates for 10 s after which it is moving at 5 m/s to the left. What was the car'
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Answer:

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A 46.8-g golf ball is driven from the tee with an initial speed of 58.8 m/s and rises to a height of 24.7 m. (a) Neglect air res
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a) the kinetic energy of the ball at its highest point is 69.58 J

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K.Ef  = 80.904 - 11.3284

K.Ef = 69.58 J

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so our raw height h' will be ( 24.7 m - 8.11 m) = 16.59 m

so our velocity will be v₂

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K.Ei + P.Ei = KEh + PEh

1/2mv² + 0 J = 1/2mv₂² + mgh'

1/2mv₂² = 1/2mv² - mgh'

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