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IgorLugansk [536]
3 years ago
11

The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 o

unces with a sample standard deviation of 0.5 ounces. At the 0.05 level of​ significance
Physics
1 answer:
shepuryov [24]3 years ago
4 0

Complete Question

The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 ounces with a sample standard deviation of 0.5 ounces. At the 0.05 level of significance,perform a hypothesis test to see if the true mean weight is  less than 4 ounce.

Answer:

Yes the true mean weight is less than 4 ounce

Explanation:

  From the question we are told that

     The random sample is n = 15

       The mean weight is \= x = 3.8\  ounce

        The standard deviation is  \sigma = 0.5 \ ounce

         The  level of significance is  \alpha  = 0.05

       

So

   The  null hypothesis is  H_o : \mu \ge 4

     The alternative hypothesis is H_a : \mu < 4

Generally the critical value which a bench mark to ascertain whether the null hypothesis is  true or false is mathematically represented as

            t_{0.05} = 1.79

This value is  obtained from  the critical value table

Generally the test statistics is mathematically represented as

                Test \ Statistics (ST)  = \frac{\= x - \mu }{\frac{\sigma}{\sqrt{n} }  }

           =>  ST = \frac{3.8 -4 }{\frac{0.5}{\sqrt{20} } }

                ST = - 1.79

So since ST is less than t_{0.05}  then the null hypothesis would be rejected and the alternative hypothesis would be accepted so

  Thus the true mean weight is less than 4

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A wheel, starting from rest, rotates with a constant angular acceleration of 1.80 rad/s^2. During a certain 7.00 s interval, it
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Answer:

a) 1.3 rad/s

b) 0.722 s

Explanation:

Given

Initial velocity, ω = 0 rad/s

Angular acceleration of the wheel, α = 1.8 rad/s²

using equations of angular motion, we have

θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²

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1.3 = 1.8 * t1

t1 = 1.3/1.8

t1 = 0.722 s

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