1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Inessa05 [86]
4 years ago
9

What is an oscillation on waves?

Physics
2 answers:
Tasya [4]4 years ago
6 0
The number of repetitions per second is called the frequency and is the inverse of the period. The period, T, is normally measured in seconds, and the frequency, ν, in Hertz. When the oscillations<span> (or vibrations) affect the material around them a </span>wave <span>is formed which transports energy away.</span>
Zolol [24]4 years ago
5 0
It vibrates and transports energy (;
You might be interested in
Three rocks, each of varying mass and volume, are released from a window at the same time. The window is at height h above the g
krek1111 [17]

Under the assumption that the three rocks are dropped from the same height, they will hit the ground at the same speed. The gravity of Earth is virtually the same for any object that is small compared to the size of the Earth. The acceleration will change with the distance from the Earth, but this change is so small for the range of heights we work with (consider the range of heights from sea level to the tip of Mount Everest) that we can take the average value and assume it to be constant. This constant value of acceleration due to Earth's gravity is 9.80665m/s²


Because the objects fall under the same constant acceleration, they will hit the ground at the same speed.

4 0
3 years ago
A 0.42 kg shuffleboard disk is initially at rest when a player uses a cue to increase its speed to 4.2 m/s at constant accelerat
MariettaO [177]

Answer

given,

mass of the shuffleboard disk = 0.42 kg

speed of the cue is increased to = 4.2 m/s

acceleration takes over 2 m then acceleration is zero.

the disk additionally slide to 12 m

final speed of disk = 0 m/s

a) increase in thermal energy

\Delta E_t = \dfrac{1}{2}m(v_1^2-v_2^2)

\Delta E_t = \dfrac{1}{2}\times 0.42 \times (4.2^2-v_2^2)

\Delta E_t = 3.704\ J

b)  \Delta E_t = F_f.d

F_f is the frictional force

     3.704= 12.F

      F_f = 0.308\ N

increase in thermal energy for entire movement of 14 m

     \Delta E_t = 0.308\times 14

     \Delta E_t =4.312 \ J

c)  Work done on the disk by the cue

  W = \Delta KE + \Delta E_{t}

  W = \dfrac{1}{2}\times 0.42 \times (4.2^2-0^2)+ F_f \times d

  W = 3.704+ 0.308 \times 2

   W = 3.704 + 0.616

   W  = 4.32 J

3 0
4 years ago
A blank is a statement the summerizes a pattern found in nature
MrMuchimi
What are you asking here?
4 0
3 years ago
You are designing a new piece of fishing equipment that will allow you to catch a fish from the surface. You know that water ref
OleMash [197]

Answer:

Law of refraction

Explanation:

An experiment to analyze the refraction of light in water can easily be performed with a laser pointer and protractor.

We throw the fishing rod line into the water, place the protractor at the point where the line touches the water and use the direction of the line for the direction of the laser pointer (on), the laser is visible by the reflection on the particles in the air.

The vertical line is called Normal and all angles must be measured with respect to this reference in optics.

Having these angles and the refractive index of water we can use the law of refraction

         n₁ sin θ₁  = n₂ sin θ₂

         θ₂ = sin^{-1} ( \frac{n_1}{n_2} \ sin \ \theta_1 )

we can repeat several times to analyze several different input points (different angles) and to decrease the errors in the measurements.

the refractive index of air is n1 = 1 and n2= 1.33  (water)

4 0
3 years ago
A student removes a 10.5 kg stereo amplifier from a shelf that is 1.82 m high. The amplifier is lowered at a constant speed to a
Nonamiya [84]

Answer:

(a) the work done by the student is 110.1 J

(b) The gravitational force that acts on the amplifier is 102.9 N

Explanation:

Given;

mass of the amplifier, m = 10.5 kg

initial position of the amplifier, x₀ = 1.82 m

final position of the amplifier, x₁ =0.75 m

The dispalcement of the amplifier Δx = x₁ - x₀ = 1.82 m - 0.75 m = 1.07 m

(b) The gravitational force that acts on the amplifier;

F = mg

F = 10.5 x 9.8

F = 102.9 N

(a) the work done by the student is calculated as;

W = FΔx

W = 102.9 x 1.07

W = 110.1 J

7 0
3 years ago
Other questions:
  • (a) Suppose that a NASCAR race car is moving to the right with a constant velocity of +82 m/s. What is the average acceleration
    12·1 answer
  • The magnitude of the electric force between two protons is 2.3x10-26 n. how far apart are they?
    13·1 answer
  • Why would an atomic nucleus give off a particle?
    14·1 answer
  • The Ptolemaic theory of the universe was disproved by
    7·1 answer
  • A ball rolls from point A to point B. The total energy of the ball at point A isn’t the same as the sum of its potential energy
    5·2 answers
  • The magnet below is cut in half. what will be the result?
    5·2 answers
  • From a static hot air balloon, a 10kg projectile is launched at a speed of 10m / s upwards. If the balloon has a mass of 90kg. W
    10·1 answer
  • Select the correct answer from each drop-down menu.
    14·2 answers
  • a convex mirror has a focal length of 0.20 metre calculate the distance of the image of an object placed 0.30 cm from the mirror
    13·1 answer
  • 3) connect two lamps to a power supply in series and current drawn from the power supply is is. connect the same two lamps in pa
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!