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3 years ago

The product of voltage times amperage is what

Physics

2 answers:

lions [1.4K]3 years ago

6 0

Answer:

batteries

Explanation:

pls give brainliest im almost lvled up.

ExtremeBDS [4]3 years ago

5 0

Answer:

The product of (voltage) times (current, in Amperes) is POWER.

Explanation:

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There is evidence that elephants communicate via infrasound, generating rumbling vocalizations as low as 14 Hz that can travel u

amid [387]

Answer:

$L = 96.2 dB$

Explanation:

As we know that the level of intensity is given as

$\beta = 10Log(\frac{I}{I_o})$

here we know

$\beta = 104 dB$

$104 = 10Log(\frac{I}{10^{-12}})$

$I = 0.025 W/m^2$

now the sound is travelling in all possible directions so we have

$\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}$

$\frac{0.025}{I_2} = \frac{10^2}{4.1^2}$

$I_2 = 4.2 \times 10^{-3} W/m^2$

now for level of sound we have

$L = 10Log(\frac{4.2 \times 10^{-3}}{10^{-12}})$

$L = 96.2 dB$

5 0

3 years ago

Would you expect to weigh more on an ocean beach or on top of a mountain? Explain.

frosja888 [35]

Answer:

An Ocean beach

Explanation:

a Ocean beach is far heavier than the top of a mountain, despite that a mountain is made with many heavy rocks a Ocean beach may have light sand but the layers of sand and the width would be way heavier then the top of a mountain.

7 0

3 years ago

How old is a bone if it still has 50% of its carbon-14 content?

Degger [83]

Answer:

5730 years

Explanation:

The half life of carbon-14 is 5730 years. If 50% of the carbon-14 remains, then exactly 1 half life has passed.

The half-life equation is:

A = A₀ (½)^(t / T)

where A is the remaining amount,

A₀ is the initial amount,

t is time,

and T is the half life.

In this case, A = ½ A₀ and T = 5730.

½ A₀ = A₀ (½)^(t / 5730)

½ = (½)^(t / 5730)

1 = t / 5730

t = 5730

6 0

3 years ago

A track star in the broad jump goes into the jump at 12 m/s and launches himself at 20° above the horizontal. How long is he in

emmainna [20.7K]

Explanation:

It is given that,

Initial speed of the broad jump, u = 12 m/s

It is launched at an angle of 20 degrees above the horizontal. Let t is the time for which the track star i in the air before returning to Earth. The motion of the track star in the broad jump can be treat as the projectile motion. The time of flight of the projectile is given by :

$t=\dfrac{2u\ sin\theta}{g}$

Putting all the values in above equation as :

$t=\dfrac{2\times 12\times \ sin(20)}{9.8}$

t = 0.837 seconds

So, the time for which the track star is in air is 0.837 seconds. Hence, this is the required solution.

3 0

3 years ago

If you have to stop on an incline, your stopping distance will be __________ on a flat surface.

Nataliya [291]

Not as far on a flat surface

5 0

4 years ago