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2 years ago

Translate the following phrase to a mathematical expression. Then, evaluate the expression for n = 5.

Mathematics

1 answer:

Feliz [49]2 years ago

5 0

Answer:

The answer is B.

Step-by-step explanation:

Quotient = Division.

So, 20÷n=?

Then it says n=5, So 20÷5=?

20÷5= 4

Hope this helps youuuu (:

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Help me please thanks

morpeh [17]

Mr Poole said n word sorry can't answer

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3 years ago

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What is f(x) = 2x2 + 28x – 5 written in vertex form? f(x) = 2(x + 7)2 – 19 f(x) = 2(x + 7)2 – 103 f(x) = 2(x + 14)2 – 14 f(x) =

padilas [110]

Answer:

f(x)=2(x+7)^2-103

Step-by-step explanation:

$f(x)=2x^{2} +28x-5\\=2(x^2+14x)-5\\=2(x^2+2(7)x+7^2-7^2)-5\\=2(x+7)^2-2(49)-5\\=2(x+7)^2-103$

6 0

3 years ago

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What is the missing number?

Annette [7]

Answer:

Missing number is 8

Step-by-step explanation:

6 0

2 years ago

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Use complete sentences to describe why √-1 ≠ -√1

tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

Definition

$\displaystyle \large{ {y}^{2} = x} \\ \displaystyle \large{ y = \pm \sqrt{x} }$

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

Definition II

$\displaystyle \large{ {a}^{2} = a \times a = |b| }$

Where b is the result from a×a. Let's see an example.

Examples

$\displaystyle \large{ {2}^{2} = 2 \times 2 = 4} \\ \displaystyle \large{ {( - 2)}^{2} = ( - 2) \times ( - 2) = | - 4| = 4}$

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

$\displaystyle \large{ {y}^{2} = - 1}$

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

$\displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{ - 1} }$

Then where does plus-minus come from? It comes from one of Absolute Value propety.

Absolute Value Property I

$\displaystyle \large{ \sqrt{ {x}^{2} } = |x| }$

Solving absolute value always gives the plus-minus. Therefore...

$\displaystyle \large{ y = \pm \sqrt{ - 1} }$

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

$\displaystyle \large{ {y}^{2} = 1} \\ \displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{1} } \\ \displaystyle \large{ y = \pm \sqrt{1} }$

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

Conclusion

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0

2 years ago

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After a car is purchased, the value of a new car decreases $4000 each year. After 3 years, the car is worth $18000.

Over [174]

Original - 4000x

so, after 3 years we have: 

Original - 12000 = 18000 

=> Original = $30,000

6 0

3 years ago