Answer:
The benchmarking function of budgeting system involves the evaluation of performance of managers.
The correct answer is C
Explanation:
The integration of inputs from different business inputs and function is done at the planning stage of budgeting. It does not involve benchmarking.
Budgeting requires requires close cooperation between accountants and operational personnel. This is referred to as active participation in budgeting. It helps to overcome behavioural challenges of budgeting.
Budget figures are used to evaluate the performance of managers. This is a benchmarking function of budgeting because it involves the comparison of performance of managers with established criteria so as to determine their level of success.
The budget outlines a specific course of action for the coming year. This indicates that a budget is a financial plan that outlines future courses of action. This does not require benchmarking.
Based on the information the amount of penalty that Victoria will have to pay is $850.
<h3>Penalty amount:</h3>
Using this formula
Penalty amount=(Tax return×Tax rate)×2
Where:
Tax return=$8,500
Tax rate=5%
Let plug in the formula
Penalty amount=( $8,500 x 5%) x 2
Penalty amount=$425×2
Penalty amount=$850
Inconclusion the amount of penalty that Victoria will have to pay is $850.
Learn more about penalty here:brainly.com/question/1178265
The answer is: Level 1 – Full Activation
In this level, the state would give a notification to all states' supporting agencies that a start plan is about to be implemented. The Division of Emergency Management personnel would soon take control to organize these agencies and assign them with each of their own roles.
Answer:
Solution:
A.
p_x=3, G_x=\frac {100}{3}=33\frac{1}{3}p
x
=3,G
x
=
3
100
=33
3
1
p_y=5, G_y=\frac{100}{5}=20p
y
=5,G
y
=
5
100
=20
B.
100-0.25\times 100=75100−0.25×100=75
p_x=3, G_x=\frac {75}{3}=25p
x
=3,G
x
=
3
75
=25
p_y=5, G_y=\frac{75}{5}=15p
y
=5,G
y
=
5
75
=15
C.
p_x=6, G_x=\frac {100}{6}=16\frac{2}{3}p
x
=6,G
x
=
6
100
=16
3
2
D.
p_y=5, G_y=\frac{100}{4}=25p
y
=5,G
y
=
4
100
=25
2.
MU_x=68-60=8, p_x=2MU
x
=68−60=8,p
x
=2
MU_y=29-25=4, p_y-?MU
y
=29−25=4,p
y
−?
\frac {MU_x}{p_x}=\frac{MU_y}{p_y}
p
x
MU
x
=
p
y
MU
y
\frac{8}{2}=\frac {4}{p_y}
2
8
=
p
y
4
p_y=1p
y
=1
