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Effectus [21]
3 years ago
13

What are the 11 chemical elements that are gases at room temperature and pressure?

Chemistry
1 answer:
sineoko [7]3 years ago
5 0
Oxygen hydrogen helium argon xenon krypton
neon nitrogen radon chlorine bromine fluorine
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If an area has high air pressure and low humidity, what type of weather will it most likely have?
elixir [45]

Aloha~! My name is Zalgo and I am here to help you out today. Those sort of conditions could be fore-boding/foreshadowing/warning that there will soon be a storm or that it will rain quite a lot. In the case of it being a storm, you should be a small room where there are no windows and nothing that is small that will fly towards you that could kill you.

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3 years ago
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What is the use of a pedigree chart? Please do not answer wat a perigee chart is!.
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Pedigree charts are used to see traits that are present in families or individuals. For example, it can be used see if certain diseases are running through someone's family and if that individual will inherit the disease.
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3 years ago
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It is important to understand the differences between chemical and physical changes. Chemical changes result in new substances,
Marysya12 [62]

Answer:

Melting of ice

Explanation:

A physical change is one in which just the physical properties of the matter is altered. Most phase changes reaction falls under this type of change.

  • Examples are boiling, melting, freezing, condensation, sublimation, magnetization of metals, breaking glass, cutting wood.
  1. No new kinds of matter is formed.
  2. The process is reversible
  3. No change in mass
7 0
3 years ago
How many liters of ammonia (NH3), at 3.2 atm and 23C, must be used to produce of 2.65 grams of calcium hydride (CaH2). 6 Ca(s)
7nadin3 [17]

Answer:

The answer to your question is    V = 0.32 L

Explanation:

Data

Volume of NH₃ = ?

P = 3.2 atm

T = 23°C

mass of CaH₂ = 2.65 g

Balanced chemical reaction

               6Ca  +  2NH₃   ⇒   3CaH₂  +  Ca₃N₂

Process

1.- Convert the mass of CaH₂ to moles

-Calculate the molar mass of CaH₂

 CaH₂ = 40 + 2 = 42 g

                             42 g ------------------ 1 mol

                              2.65 g --------------  x

                              x = (2.65 x 1)/42

                              x = 0.063 moles

2.- Calculate the moles of NH₃

                     2 moles of NH₃ --------------- 3 moles of CaH₂

                      x                        --------------- 0.063 moles

                                x = (0.063 x 2) / 3

                                x = 0.042 moles of NH₃

3.- Convert the °C to °K

Temperature = 23°C + 273

                      = 296°K

4.- Calculate the volume of NH₃

-Use the ideal gas law

              PV = nRT

-Solve for V

                V = nRT / P

-Substitution

                V = (0.042)(0.082)(296) / 3.2

-Simplification

               V = 1.019 / 3.2

-Result

               V = 0.32 L

7 0
2 years ago
The decomposition of N2O4 into NO2 has Kp = 2. Some N2O4 is placed into an empty container, and the partial pressure of NO2 at e
Sunny_sXe [5.5K]

Answer: Option (B) is the correct answer.

Explanation:

Expression for the given decomposition reaction is as follows.

           N_{2}O_{4} \rightarrow 2NO_{2}

Let us assume that x concentration of N_{2}O_{4} is present at the initial stage. Therefore, according to the ICE table,

                    N_{2}O_{4} \rightarrow 2NO_{2}

Initial :               x                   0

Change :       - 0.1        2 \times 0.1

Equilibrium : (x - 0.1)             0.2

Now, expression for K_{p} of this reaction is as follows.

     K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}

Putting the given values into the above formula as follows.

          K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}

                 2 = \frac{(0.2)^{2}}{(x - 0.1)}

                2 \times (x - 0.1) = (0.2)^{2}

                            x = 0.12

This means that P_{N_{2}O_{4}} = x = 0.12 atm.

Thus, we can conclude that the initial pressure in the container prior to decomposition is 0.12 atm.

6 0
3 years ago
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