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AlekseyPX
3 years ago
12

in this lab you observed that each element emits a unique color of light when heated in a flame. If these light emissions were e

xamined through a prism, you would observe that the emitted light is actually composed of different wavelengths of light that may lie in the violet region, the green region, or the red region of the visible spectrum. Each element has a unique emission spectrum. Look up the emission spectra for the element tested in this lab. Do research on how scientists apply these emission spectra to investigate the chemical composition pf stars. For example what is the emission spectrum of the sun, and what does this spectrum reveal about the types of elements in the sun

Chemistry
2 answers:
kotykmax [81]3 years ago
7 0

Answer:

The sun's emission spectrum contains most of the visible spectrum, and it also contains UV light and infrared radiation. The colour depends on the atom, like oxygen, which can be found in the sun, is responsible for the colours red and green.

il63 [147K]3 years ago
7 0

Answer:

<u>The solar emission spectrum show us all the elements that are part of the sun</u>. This spectrum is called Fraunhofer Lines after its discovery by  a German physicist named Joseph von Fraunhofer

Explanation:

When looking  at emission spectrums, keep in mind, the black lines represent the element that is making part of the studied object.

The black lines that appear in the sun emission spectrum, are named "Fraunhofer Lines" and each one is represented by a letter, as we can see in the image below.

Letters A and B , are made by the Oxygen from our atmosphere.

Letter C: Hydrogen α

Letter D: Sodium

Letter E: Iron

Letter F: Hydrogen β

Letter G: Iron

Letter H: Calcium

Letter K: Calcium

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A solution is prepared by dissolving 15.0 g of NH3 in 250.0 g of water. The density of the resulting solution is 0.974 g/mL. The
iVinArrow [24]

Answer:

[NH₃]  → 3.24 M  

Explanation:

Our solute: Ammonia

Our solvent: Water

Solution's mass = Mass of solute + Mass of solvent

Solution's mass = 15 g + 250 g = 265g

We use density to determine, the volume.

D = mass /volume → Volume = m / D →  265 g /0.974 g/mL = 272.07 mL.

We convert the mL to L → 272.07 mL . 1L /1000mL = 0.27207 L

To determine molarity we need the moles of solute in 1 L of solution.

Moles of solute are: 15g / 17g/mol = 0.882 moles

[NH₃] = 0.882mol /0.27207 L → 3.24 M  

3 0
3 years ago
What pressure is required to compress 196.0 liters of air at 1.83 atmosphere into a cylinder whose volume is 26.0 liters
drek231 [11]

Answer:

P₂ = 13.79 atm

Explanation:

Given data:

Initial volume = 196.0 L

Initial pressure = 1.83 atm

Final volume = 26.0 L

Final pressure = ?

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.83 atm × 196.0 L = P₂× 26.0 L

P₂ = 358.68 atm. L /  26.0 L

P₂ = 13.79 atm  

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3 years ago
An ethylene gas torch requires 300 L of gas at 0.8 atm. What will be the pressure of the gas if ethylene is supplied by a 200.0
Vlad [161]

Answer:

1.2 atm

Explanation:

Given data

  • Volume of the gas in the tank (V₁): 200.0 L
  • Pressure of ethylene gas in the tank (P₁): ?
  • Volume of the gas in the torch (V₂): 300 L
  • Pressure of the gas in the torch (P₂): 0.8 atm

If we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.

P_1 \times V_1 = P_2 \times V_2\\P_1 = \frac{P_2 \times V_2}{V_1} = \frac{0.8atm \times 300L}{200.0L} = 1.2 atm

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What is the heat of reaction (AH) of the<br> following?<br> C(s) + O2 (g) --&gt; CO2 (g)
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Answer:

C co2 2co enthalpy

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What is the role of plastocyanin in the z-scheme model?
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