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I am Lyosha [343]

2 years ago

8

From which source is pomace derived? (1 point)

1 answer:

GrogVix [38]2 years ago

6 0

Answer: unused waste from food processing

Explanation: have you takin the chemical reaction system unit test yet? It’s alternated

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Plsssss give me answer<br>

34kurt

Explanation:

Medieval number one. There you havt it.

4 0

10 months ago

1. The electronegativities of the period-3 elements are listed on the transparency. Calculate the

Firdavs [7]

The correct answer is c. Please give me brainlest let me know if it’s correct or not thanks bye

8 0

2 years ago

Determine the value of the equilibrium constant, KgoalKgoalK_goal, for the reaction CO2(g)⇌C(s)+O2(g)CO2(g)⇌C(s)+O2(g), Kgoal=?

NISA [10]

Answer:

The value of the equilibrium constant for reaction asked is $1.24\times 10^{-7}$ .

Explanation:

$CO_2(g)\rightleftharpoons C(s)+O_2(g)$

$K_{goal}=?$

$K_{goal}=\frac{[C][O_2]}{[CO_2]}$

$2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2(g)$ ..[1]

$K_1=\frac{[CH_3COOH][O_2]^2}{[CO_2]^2[H_2O]^2}$

$2H_2(g)+O2(g)\rightleftharpoons 2H_2O(l)$ ..[2]

$K_2=\frac{[H_2O]^2}{[H_2]^2[O_2]}$

$CH_3COOH(l)\rightleftharpoons 2C(s)+2H_2(g)+O_2(g)$ ..[3]

$K_3=\frac{[C]^2[H_2]^2[O_2]}{[CH_3COOH]}$

[1] + [2] + [3]

$2CO_2(g)\rightleftharpoons 2C(s)+2O_2(g)$

( on adding the equilibrium constant will get multiplied with each other)

$K=K_1\times K_2\times K_3$

$K=5.40\times 10^{-16}\times 1.06\times 10^{10}\times 2.68\times 10^{-9}$

$K=1.53\times 10^{-14}$

$K=\frac{[C]^2[O_2]^2}{[CO_2]^2}$

On comparing the K and $K_{goal}$ :

$K^2=K_{goal}$

$K_{goal}=\sqrt{K}=\sqrt{1.53\times 10^{-14}}=1.24\times 10^{-7}$

The value of the equilibrium constant for reaction asked is $1.24\times 10^{-7}$ .

4 0

2 years ago

Calculate how many grams of oxygen form when each quantity of reactant completely reacts.. . 2HgO----->2Hg+O2

goblinko [34]

<span>6.96g HgO
hope it helps.
</span>

3 0

2 years ago

HELP................!!!!

expeople1 [14]

Your answer is 1-3-2-4 , grass sand water rock

3 0

2 years ago