3Na2O(at) + 2Al(NO3)3(aq) —> 6NaNO3(aq) + Al2O3(s)
This is a double replacement reaction and NaNO3 is aqueous because Na is an alkali metal, plus nitrate is in the solution. Both of these are soluble. Al2O3 is not soluble because it does not contain any element that is soluble and is hence the precipitate.
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The mass percentage of water (H₂O) in cadmium chloride tetra hydratesolution is equal to the 28.2%.
<h3>How do we calculate mass percentage?</h3>
Mass percentage of any substabce present in any solution will be calculated as:
Mass percent = (Mass of substance/Total mass of solution)×100%
According to the question,
Mass of water (H₂O) = 18.02 g/mol
Mass of solvent (CdCl₂.4H₂O) = 183.32 + 4(18.02) = 255.4 g/mol
On putting values, we get
Mass percent = (18.02 / 255.4) × 100% = 28.2%
Hence mass percent of water is 28.2%.
To know more about mass percent, visit the below link:
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5.5/-38 / 5.5 = 1/-6.9 x 1.3 = 1.3/-8.98
unit volume/temperature x searching amount
i’d say the temperature would be -8.98 C simply - I don’t know what formula youd use for this
Answer:
See explanation
Explanation:
The mechanism of this reaction including intermediates are shown in the image attached to this answer.
The reaction of HBr with 3-bromocyclohexene yields trans-1,2-dibromocyclohexane as the sole product because; the proton first attacks the 3-bromocyclohexene and a brominium ion is formed. This brominium ion is a cyclic intermediate as shown in the image attached.
Attack of a bromine ion afterwards must lead to the formation of trans-1,2-dibromocyclohexane as shown.
<span>Molality(m) or molal concentration is a measure
of concentration and it refers to amount of substance in a specified amount of
mass of the solvent. Used unit for molality is mol/kg which is also
sometimes denoted as 1 molal. It is equal to the moles of solute (the substance
being dissolved) divided by the kilograms of solvent (the substance used to
dissolve).</span>
Molarity(M) or molar concentration is also a
measure of concentration and represents the amount of substance per unit volume
of solution(number of moles per litre of solution. Used unit for molarity is
mol/L or M. A solution with a concentration of 1 mol/L is equivalent to 1 molar
(1 M).
Molality is preferred when
the temperature of the solution varies, because it does not depend on
temperature, (neither number of moles of solute nor mass of solvent will be affected
by changes of temperature), while molarity changes as temperature changes(volume
of solution changes as temperature changes).
