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Minchanka [31]
2 years ago
12

Hello people ~

Chemistry
2 answers:
Klio2033 [76]2 years ago
8 0
<h3>CHEMISTRY</h3>

What is the most basic aromatic amine’s common name?

a) Benzenamine

b) Benzylamine

c) Aniline

d) Aminobenzene

#BRAINLYEVERYDAY

Pavel [41]2 years ago
8 0

Answer:

<em><u>BENZYLAMINE </u></em>

Explanation:

  • <em><u>most basic aromatic amine’s common </u></em><em><u>name </u></em><em><u>is </u></em><em><u>BENZYLAMINE</u></em>
  • <em><u>C6H5C2</u></em><em><u>NH2</u></em><em><u> </u></em><em><u>IS </u></em><em><u>FORMULA </u></em>

<em><u>O</u></em><em><u>PTION </u></em><em><u>B </u></em><em><u>~</u></em>

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grandymaker [24]

Answer:

Formation of sedimentary rocks

Explanation:

I believe this is correct, May I get a brainliest???

3 0
3 years ago
In sience is copper a element or not a element
sukhopar [10]

Answer:

a element

Explanation:

In science copper is a element. It is one of the transition metals found on the periodic table of elements.

Elements are distinct substances that cannot be split-up into simpler substances. Such substances consist of one kind of atom.

There are over a hundred elements that are known till date.

Each elements combines to form a compound

7 0
3 years ago
The hydrogen gas produced is collected over water at 25.0 oC. The volume of the gas is 7.80 L, and the total pressure in the gas
Eva8 [605]

Answer:

20.4 grams Zn

Explanation:

To find the mass, you first need to find the moles. This can be found using the Ideal Gas Law equation:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

Before you can plug the values into the equation, you need to convert Celsius to Kelvin.

P = 0.980 atm                   R = 0.08206 atm*L/mol*K

V = 7.80 L                          T = 25.0 °C + 273.15 = 298.15 K

n = ? moles

PV = nRT

(0.980 atm)(7.80 L) = n(0.08206 atm*L/mol*K)(298.15 K)

7.644 = n(24.466)

0.312 moles = n

Now that you have the number of moles, you can convert it to grams using the atomic mass of zinc. The final answer should have 3 sig figs to match the sig figs in the given values.

Atomic Mass (Zn): 65.380 g/mol

0.312 moles Zn           65.380 grams
-------------------------  x  -------------------------  =  20.4 grams Zn
                                         1 mole

5 0
1 year ago
Question 20 (2 points)
sveta [45]

Answer:

becomes runoff and finds its way back to the ocean

Explanation:

Precipitation refers to rainfall that reaches the earth.

Most of the rainfall that reaches the earth becomes runoff and finds its way back to the ocean.

When the rain falls on earth, some evaporates, some enters into the ground while some runs off into rivers and streams. Almost all of the rain water flows into the oceans or other bodies of water.

Hence, most of the rainfall that reaches the earth becomes runoff and finds its way back to the ocean

7 0
3 years ago
A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm
Ulleksa [173]

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100

Percent error = \frac{0.1}{63.2}\times 100

Percent error = 0.00158\times 100

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100

Percent error = \frac{0.2}{63.2}\times 100

Percent error = 0.00316\times 100

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100

Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100

Percent error = \frac{(0.5)}{63.2}\times 100

Percent error = 0.00791\times 100

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%




7 0
3 years ago
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