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Minchanka [31]
3 years ago
12

Hello people ~

Chemistry
2 answers:
Klio2033 [76]3 years ago
8 0
<h3>CHEMISTRY</h3>

What is the most basic aromatic amine’s common name?

a) Benzenamine

b) Benzylamine

c) Aniline

d) Aminobenzene

#BRAINLYEVERYDAY

Pavel [41]3 years ago
8 0

Answer:

<em><u>BENZYLAMINE </u></em>

Explanation:

  • <em><u>most basic aromatic amine’s common </u></em><em><u>name </u></em><em><u>is </u></em><em><u>BENZYLAMINE</u></em>
  • <em><u>C6H5C2</u></em><em><u>NH2</u></em><em><u> </u></em><em><u>IS </u></em><em><u>FORMULA </u></em>

<em><u>O</u></em><em><u>PTION </u></em><em><u>B </u></em><em><u>~</u></em>

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A 2.0 mL sample of air in a syringe exerts a pressure of 1.02 atm at 22 C. If that syringe is placed into boiling water at 100 C
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Answer: The new volume of the air in the syringe is 7.3 mL.

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Given: V_{1} = 2.0 mL,     P_{1} = 1.02 atm,          T_{1} = 22^{o}C

V_{2} = ?,               P_{2} = 1.27 atm,               T_{2} = 100^{o}C

Formula used to calculate the new volume in syringe is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{1.02 atm \times 2.0 mL}{22^{o}C} = \frac{1.27 atm \times V_{1}}{100^{o}C}\\V_{1} = 7.3 mL

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