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Greeley [361]
3 years ago
14

Provide an explanation at the subatomic level to explain why different colors are observed for different metal salts.

Chemistry
2 answers:
lakkis [162]3 years ago
8 0

Answer:

When you heat an atom, some of its electrons are "excited* to higher energy levels. When an electron drops from one level to a lower energy level, it emits a quantum of energy. ... The different mix of energy differences for each atom produces different colours. Each metal gives a characteristic flame emission spectrum.

Explanation:

Solnce55 [7]3 years ago
6 0

Answer:

Due to difference in the electronic energy level of atoms in different metals.

Explanation:

The subatomic particles are protons, electrons and neutrons.

When we talk about colors, the subatomic particle involved is electron.

An atom of a metal absorbs light and in this process the electrons gets exited (gain energy) and when they come back to ground state they emit light and thus the color appears.

In case of different metals the energy required for excitation of electrons is different (due to difference in the arrangement of electrons in the orbitals and difference in effective nuclear charge), thus the electrons in different metal atoms absorb light of different of wavelengths and end up in appearance of different colors.

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A 85.4 lb child has a Streptococcus infection. Amoxicillin is prescribed at a dosage of 45 mg per kg of body weight per day give
bixtya [17]

The amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.

<h3>What is the amount of Amoxicillin dose given to the child?</h3>

The amount of  Amoxicillin  dose given to the child is calculated as follows;

amount of Amoxicillin dose = weight of the child x dosage prescribed

<h3>What is the weight of the child in pounds (lb) </h3>

The weight of the child in pounds (lb) is calculated as follows;

1 lb = 0.453592 kg

85.4 lb = ?

= 85.4 x 0.453592 kg

= 38.74 kg

amount of Amoxicillin dose = 38.74 kg x 45 mg/kg

amount of Amoxicillin dose = 1,743.3 mg

Thus, the amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.

Learn more about amount of dose here: brainly.com/question/11185154

#SPJ1

The complete question is below:

A 85.4 lb child has a Streptococcus infection. Amoxicillin is prescribed at a dosage of 45 mg per kg of body weight per day given b.i.d. Calculate the daily dose of the child.

7 0
1 year ago
Which image shows 2-hexyne?
MaRussiya [10]

Answer: C

Explanation:

A. Shows 3-Hexyne (NOT 2-HEXYNE)

B. Shows 7 carbons (too many) (NOT 2-HEXYNE)

C. Shows a triple bond (yne) and 6 carbons and it's on the second carbon (2-HEXYNE)

D. Shows two substitent on the second carbon but the triple bond is on the 3rd carbon so it's 2,2-dimethyl-3-heptyne (NOT 2-HEXYNE)

4 0
2 years ago
What are the concentrations of hydroxide and hydronium ions in a solution with a pH of 10.2? 1.4 × 10–4 M H3O+ and 7.1 × 10–11 M
kap26 [50]

Answering:

It is D

Explanation:

Just took the test

8 0
3 years ago
A weak monoprotic acid is titrated with 0.100 MNaOH. It requires 50.0 mL of the NaOH solution to reach the equivalence point. Af
larisa86 [58]

Explanation:

The given reaction is as follows.

        HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)

Hence, number of moles of NaOH are as follows.

        n = 0.05 L \times 0.1 M

           = 0.005 mol

After the addition of 25 ml of base, the pH of a solution is 3.62. Hence, moles of NaOH is 25 ml base are as follows.

             n = 0.025 L \times 0.1 M

                = 0.0025 mol

According to ICE table,

         HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)

Initial:     0.005 mol   0.0025 mol              0                  0

Change: -0.0025 mol  -0.0025 mol        +0.0025 mol

Equibm:   0.0025 mol    0                         0.0025 mol

Hence, concentrations of HA and NaA are calculated as follows.

          [HA] = \frac{0.0025 mol}{V}

        [NaA] = \frac{0.0025 mol}{V}

       [A^{-}] = [NaA] = \frac{0.0025 mol}{V}

Now, we will calculate the pK_{a} value as follows.

          pH = pK_{a} + log \frac{A^{-}}{HA}

       pK_{a} = pH - log \frac{[A^{-}]}{[HA]}

                  = 3.42 - log \frac{\frac{0.0025 mol}{V}}{\frac{0.0025}{V}}

                  = 3.42

Thus, we can conclude that pK_{a} of the weak acid is 3.42.

           

8 0
3 years ago
I WILL MARK BRAINIEST PLEASE HELP QUICKLY!!
omeli [17]

Answer:

6CO2 + 6H2O → C6H12O6 + 6O2 is a balanced equation

Explanation:

Carbon, Oxygen, Hydrogen

Reactants are carbon dioxide and water, products are glucose and oxygen

Dynamic Equilibrium I have no idea about (soz)

I believe this might be endothermic

4 0
3 years ago
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