The amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.
<h3>
What is the amount of Amoxicillin dose given to the child?</h3>
The amount of Amoxicillin dose given to the child is calculated as follows;
amount of Amoxicillin dose = weight of the child x dosage prescribed
<h3>What is the weight of the child in pounds (lb) </h3>
The weight of the child in pounds (lb) is calculated as follows;
1 lb = 0.453592 kg
85.4 lb = ?
= 85.4 x 0.453592 kg
= 38.74 kg
amount of Amoxicillin dose = 38.74 kg x 45 mg/kg
amount of Amoxicillin dose = 1,743.3 mg
Thus, the amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.
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The complete question is below:
A 85.4 lb child has a Streptococcus infection. Amoxicillin is prescribed at a dosage of 45 mg per kg of body weight per day given b.i.d. Calculate the daily dose of the child.
Answer: C
Explanation:
A. Shows 3-Hexyne (NOT 2-HEXYNE)
B. Shows 7 carbons (too many) (NOT 2-HEXYNE)
C. Shows a triple bond (yne) and 6 carbons and it's on the second carbon (2-HEXYNE)
D. Shows two substitent on the second carbon but the triple bond is on the 3rd carbon so it's 2,2-dimethyl-3-heptyne (NOT 2-HEXYNE)
Explanation:
The given reaction is as follows.

Hence, number of moles of NaOH are as follows.
n = 
= 0.005 mol
After the addition of 25 ml of base, the pH of a solution is 3.62. Hence, moles of NaOH is 25 ml base are as follows.
n = 
= 0.0025 mol
According to ICE table,

Initial: 0.005 mol 0.0025 mol 0 0
Change: -0.0025 mol -0.0025 mol +0.0025 mol
Equibm: 0.0025 mol 0 0.0025 mol
Hence, concentrations of HA and NaA are calculated as follows.
[HA] = 
[NaA] = 
![[A^{-}] = [NaA] = \frac{0.0025 mol}{V}](https://tex.z-dn.net/?f=%5BA%5E%7B-%7D%5D%20%3D%20%5BNaA%5D%20%3D%20%5Cfrac%7B0.0025%20mol%7D%7BV%7D)
Now, we will calculate the
value as follows.
pH = 
![pK_{a} = pH - log \frac{[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%3D%20pH%20-%20log%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D)
= 
= 3.42
Thus, we can conclude that
of the weak acid is 3.42.
Answer:
6CO2 + 6H2O → C6H12O6 + 6O2 is a balanced equation
Explanation:
Carbon, Oxygen, Hydrogen
Reactants are carbon dioxide and water, products are glucose and oxygen
Dynamic Equilibrium I have no idea about (soz)
I believe this might be endothermic