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statuscvo [17]
3 years ago
13

Determine the total volume of a balloon if it is inflated with 2.50g helium at 180C and 0.87atm.

Chemistry
1 answer:
puteri [66]3 years ago
5 0

Answer:

V = 267.2 L

Explanation:

Given data:

Volume of balloon = ?

Mass of helium = 2.50 g

Temperature of gas = 180°C

Pressure = 0.87 atm

Solution:

Number of moles of helium:

Number of moles = mass/molar mass

Number of moles = 2.50 g/ 4 g/mol

Number of moles = 0.625 g

Volume of helium:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

0.87 atm× V = 0.625 mol × 0.0821 atm.L/mol.K×453 K

V = 232.45 atm.L /0.87 atm

V = 267.2 L

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Write balanced nuclear equations for the following:(a) β⁻ decay of silicon-32
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7 0
1 year ago
The compound Xe(CF3)2 decomposes in afirst-order reaction to elemental Xe with a half-life of 30. min.If you place 7.50 mg of Xe
Irina-Kira [14]

Answer:

t=147.24\ min

Explanation:

Given that:

Half life = 30 min

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{30}\ min^{-1}

The rate constant, k = 0.0231 min⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 0.0231 min⁻¹

Initial concentration [A_0] = 7.50 mg

Final concentration [A_t] = 0.25 mg

Time = ?

Applying in the above equation, we get that:-

0.25=7.50e^{-0.0231\times t}

750e^{-0.0231t}=25

750e^{-0.0231t}=25

x=\frac{\ln \left(30\right)}{0.0231}

t=147.24\ min

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3 years ago
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Answer:

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Explanation:

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