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icang [17]
1 year ago
14

Coffee Shop PricesCup CostSmall $2Regular $4Large $5David and Jon are placing coffee orders for their friends.David orders 10 la

rge cups of coffee. Jon orders 4 fewer large cups than David. Jon pays for his orders with a $50 bill.Jon wants to know how much he spent on coffee.What is a good plan to find the amount Jon spent on coffee?3rd grade student
Mathematics
1 answer:
timurjin [86]1 year ago
8 0

Step 1:

Cost of large cup = $5

Step 2:

Number of large David orders = 10 cups

A good plan to find the amount Jon spent is to find the number of large cups Jon orders from the number of large cups David orders.

Jon order 4 fewer large cups

Therefore,

Jon order = 6 cups

Step 3:

A good plan to find the amount Jon spent is to find the number of large cups Jon orders from the number of large cups David orders.

The amount Jon spent on coffee = 6 x $5 = $30

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Whats the answer to this ill give brainliest
Naily [24]

Answer:

80

Step-by-step explanation:

110-180=70

30+70=100

100-180=80

8 0
3 years ago
Read 2 more answers
Simplify 2m - [n - (m - 2n)].<br><br> -3m - n<br> 3m - n<br> -3m - 3n<br> 3m - 3n
VMariaS [17]
2m - [n - (m - 2n)]

2m - n + (m - 2n)

2m - n + m - 2n

2m + m - n - 2n

3m - 3n

Answer is D.
5 0
3 years ago
Can anyone help please right answer only
BARSIC [14]

The value of x is 27°.

Solution:

Given \triangle \mathrm{ACB} \cong \Delta \mathrm{DCE}.

∠A = 3x – 10, ∠C = 45°, ∠D = 2x + 10

<em>If two triangles are congruent, then the angles are congruent.</em>

∠A = ∠E (Alternate interior angles)

∠C = ∠C (Reflexive property)

∠B = ∠D (Alternative interior angles)

⇒ ∠B = 2x + 10

<em>Sum of the interior angles of the triangle = 180°</em>

In ΔACB,

3x – 10 + 45° + 2x + 10 = 180°

5x + 45° = 180°

Subtract 45° on both sides of the equation.

5x = 135°

Divide by 5 on both sides of the equation.

x = 27°

The value of x is 27°.

7 0
3 years ago
Needed help for my math please
vesna_86 [32]

Answer:

see explanation

Step-by-step explanation:

(a)

\frac{a}{a} = 1 ( any value divided by itself = 1 )

(b)

\frac{a}{1} = a ( any value divide by 1 is the value itself )

(c)

\frac{a}{b} × \frac{c}{d} = \frac{ac}{bd}

The product of 2 fractions is the product of the numerators divided by the product of the denominators

(d)

\frac{a}{b} ÷ \frac{c}{d} = \frac{ad}{bc}

To divide 2 fractions, leave the first fraction, change division to multiplication and turn the second fraction upside down, that is

\frac{a}{b} ÷ \frac{c}{d} = \frac{a}{b} × \frac{d}{c} = \frac{ad}{bc}

(e)

\frac{a}{d} + \frac{b}{d} = \frac{a+b}{d}

Since the fractions have a like denominator, add the numerators leaving the denominator. This applies to subtraction also

(f)

\frac{a}{d} - \frac{b}{d} = \frac{a-b}{d}

See explanation for part (e)




6 0
3 years ago
Can someone help me please
yuradex [85]
I don't know what to do
4 0
3 years ago
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