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-Dominant- [34]
1 year ago
12

the criterion for whether a reaction proceeds spontaneously is delta g not delta g not, because delta g takes into account the c

oncentrations of the substrates and products
Chemistry
1 answer:
Lina20 [59]1 year ago
5 0

Yes this statement is true because the concentration is two help determine whether the reaction is moving forward or backwards direction

Here it is at standard condition and delta g not is always the same because it denote that the reactant/product are at standard temperature or product as the reaction goes toward equilibrium delta g change because reaction is proceeding forward and  delta g not is standard change in free energy between reactant and product. delta g is used to find gibbs free energy in nonstandard conditions while delta g naught is used to determine gibbs free chemical reaction energy under normal conditions. that's why this statement is true.

Know more about delta g and delta g not

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Predict the reactivity of silicon in water relative to that of sodium, magnesium, and aluminium. Explain your answer. How does t
Inessa [10]

Answer:

See explanation

Explanation:

The reactivity of metals has a lot to do with their position in the electrochemical series. However, it is also known that metallic character decreases across the period. This implies that as we move from left to right along the periodic table. Sodium, magnesium, aluminum and silicon continues to decrease in metallic character. As a matter of fact, silicon is a metalloid and not a pure metal.

Sodium reacts with cold water to give a vigorous reaction,magnesium and aluminium reacts with steam at red heat.

Silicon does not react with water, even as steam, under normal conditions.

5 0
3 years ago
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Masteriza [31]

Answer:

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7 0
3 years ago
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Which source would be the most reliable to validate a claim?
Mekhanik [1.2K]

Answer:

In general, print publications with authors and listed sources tend to be reliable because they provide sources which readers can verify. Likewise, Web postings with a .gov (posted by the United States government) are both current and reliable.

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4 0
3 years ago
What is the freezing point of a solution of 465 g of sucrose c12h22o11 dissolved in 575 ml of water?
Amanda [17]

Answer:

The freezing point of the solution is - 4.39 °C.

Explanation:

We can solve this problem using the relation:

<em>ΔTf = (Kf)(m),</em>

where, ΔTf is the depression in the freezing point.

Kf is the molal freezing point depression constant of water = -1.86 °C/m,

density of water = 1 g/mL.

<em>So, the mass of 575 mL is 575 g = 0.575 kg.</em>

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<em>∴ ΔTf = (Kf)(m</em>) = (-1.86 °C/m)(2.36 m) = <em>- 4.39 °C.</em>

<em>∵ The freezing point if water is 0.0 °C and it is depressed by - 4.39 °C.</em>

<em>∴ The freezing point of the solution is - 4.39 °C.</em>

6 0
3 years ago
1Which is a dopant for a p-type semiconductor?
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For a p type of semiconductor we need a dopant which is from 13th group in periodic table

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So the correct element will be In : Indium

The other elements belongs to 15th group and hence will give n type semiconductor


5 0
3 years ago
Read 2 more answers
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