A. Reactants, products
In a chemical reaction, reactants interact to form products
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First, we have to calculate the number of moles of H2SO4 in the solution:
V=60 mL = 0.06 L
c=5.85 mol/L
n=V×c=0.06×5.85=0.351 mol
Then we need to find the molar mass of H2SO4:
2×Ar(H) + Ar(S) + 4×Ar(O) =
=2 + 32 + 64 = 98 g/mol
Finally, we need to find the mass of H2SO4:
m=0.351 × 98 = 34.398 g
5.00 moles of a binary, group 2 oxide are found to have a mass of 521 g. The group 2 metal is Strontium.
According to question 5 moles of binary group 2 metal oxide mass =521 g
So, 1-mole metal oxide mass will be =521 / 5=104.2 g
Now, as metal oxide is group 2 oxide so metal: oxygen =1: 1
So the mass of metal is =104.2-16=88.2 gm (as the atomic mass of oxygen is 16 g
Therefore, the metal is Strontium(Sr) whose atomic mass is 87.62 g which is nearly 88.2 gm
So, the formula of metal oxide is SrO
The group two metal here is Sr which is strontium and lies in the same group as calcium.
To learn more about group 2 metals, visit:
brainly.com/question/18328178
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Answer: Rb gains two electrons
Explanation:
