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zysi [14]
3 years ago
7

How many mole are contained in 3.131x1024 particles?

Chemistry
1 answer:
Artyom0805 [142]3 years ago
7 0

Answer:

              5.12 Moles

Explanation:

                      As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Particles and Avogadro's Number is given as,

                          Number of Moles  =  Number of Particles ÷ 6.022 × 10²³

Putting values,

                          Number of Moles  =  3.131 × 10²⁴ Particles ÷ 6.022 × 10²³

                          Number of Moles  =  5.12 Moles

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When 0.34 of HNO₃ is titrated to equivalence using 0.14 l of 0.1 m NaOH then the concentration of HNO₃ is 0.041 M

The reaction of neutralization of HNO₃ with NaOH is

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When 1 mole of HNO₃ react with 1 mole of NaOH, based on chemical rection the moles of NaOH at equivalence point are equal to moles of HNO₃ present in solution: -

With the mole and volumes, we can find molarity as follows:

            Moles of NaOH = moles HNO₃

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Molarity: -

              \frac{(Mole of HNO₃)}{(volume of HNO₃)}=  \frac{0.014}{0.34}

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Thus, from above solution we concluded that the concentration of HNO₃ solution is 0.041 M.

Learn more about molarity: brainly.com/question/8732513

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Explanation:

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The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.

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