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balu736 [363]
1 year ago
5

Y varies inversely with x, y = 4 and x = 3, what is y, when x = 2B) given: y = 2x - 1 (x-3)(x+1) what is the I. VAII. HA III. X-

INTERCEPT

Mathematics
1 answer:
Semmy [17]1 year ago
4 0

SOLUTION

(a)

\begin{gathered} y\alpha\frac{1}{x} \\  \\ y=\frac{k}{x} \\  \\ 4=\frac{k}{3} \\  \\ k=12 \end{gathered}\begin{gathered} y=\frac{12}{x} \\  \\ when\text{ x=2} \\  \\ y=\frac{12}{2} \\  \\ y=6 \end{gathered}

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If you left $25.00 on your table for a $21.50 meal, what was the percent of the tip?
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I THINK it would be B.

Step-by-step explanation:

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In this exercise, we estimate the rate at which the total personal income is rising in the Richmond-Petersburg, Virginia, metrop
lyudmila [28]

Answer:

The rate at which the total personal income was rising in the Richmond-Petersburg area in 1999 is $1.627 billion per year

Step-by-step explanation:

Let t be the number of years after 1999.

From the information given:

  1. In 1999, the population in this area was 961400, and the population was increasing at roughly 9200 people per year.
  2. The average annual income was 30593 dollars per capita, and this average was increasing at about 1400 dollars per year.

The population growth can be modeled with a linear equation. The initial population was P_0 is 961400 and it grows by 9200 people per year.

The population in time t can be written

P(t)=9200t+961400

The average annual income can be modeled with a linear equation. The initial average annual income was 30593 dollars per capita and it grows by  1400 dollars per year.

A(t)=1400t+30593

If we multiply both together gives the total personal income at time t.

T(t)=P(t)\cdot A(t)\\T(t)=(9200t+961400)\cdot (1400t+30593)

The rate at which the total personal income was rising in the Richmond-Petersburg area is the derivative T(t)'

We need to use the Product Rule that says

If f and g are both differentiable, then:

\frac{d}{dx}[f(x)g(x)]=f(x)\frac{d}{dx}[g(x)] +g(x)\frac{d}{dx}[f(x)]

Applying the Product Rule

\frac{d}{dt}T(t)=\frac{d}{dt} [(9200t+961400)\cdot (1400t+30593)]\\\\T(t)'=\frac{d}{dt}\left(9200t+961400\right)\left(1400t+30593\right)+\frac{d}{dt}\left(1400t+30593\right)\left(9200t+961400\right)\\\\T(t)'=9200\left(1400t+30593\right)+1400\left(9200t+961400\right)\\\\T(t)'=12880000t+281455600+12880000t+1345960000\\\\T(t)'=25760000t+1627415600

For 1999, t = 0.

The raising is

T(0)'=25760000(0)+1627415600\\T(0)'=1,627,415,600

The rate at which the total personal income was rising in the Richmond-Petersburg area in 1999 is $1.627 billion per year.

7 0
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If x is a positive integer divisible by 6, and x < 60, what is the greatest possible value of x?
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3 years ago
your primary jobs gross income is 3468.73/month deductions are fica (7.65%) federal tax witholding (11.5%) and state tax withhol
Dmitry_Shevchenko [17]
Sierah907 Your primary job’s gross income is $3,468.73/month. Deductions are FICA (7.65%), federal tax withholding (11.5%), and state tax withholding (7.8%). How much are your fixed expenses if they are 36% of your realized income?


$1,388.65


$814.92


$912.21


$1,068.57





<span>To get your realized income you: add your deductions which equals to a total of 26.95%. 

Then you subtract that amount  from your gross income. 
(3468.72 - 26.95% = 2533.91) 

 After that you need to find what 36% of your realized income equals to: 

and it equals to, 912.20. 

Therefore, your answer is C.




Answer 2: </span>

our deductions are 7.65% , 11.5% and 7.8% . Total 26.95% .

So deduct that from your Gross . $3468.73 - 26.95% leaves you with $ 2533.91.
That's your Realized Income . $2533.91 .

So you need to find 36% of that . It's $912.20.

<span> And that is your answer . Your fixed expenses are $ 912.20 . </span>
4 0
3 years ago
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