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Nesterboy [21]
1 year ago
8

Write an equation of the line through (6,-2) with a slope of 4

Mathematics
1 answer:
torisob [31]1 year ago
3 0

Notice that for this question, they are providing you with:

1) The slope of the line (4)

2) a point on the plane through which the line goes (6, -2)

So you can directly use for this the "point-slope" form of a line which is as follows:

y-y_0=m(x-x_{0)}

This includes m as the slope, and the pair (x0, y0) as the pair representing the point the line goes through.

So, let's use the info they gave you to complete this:

y-(-2)=4(x-6)

which we can work out a little more:

y+2=4x-24

And even a little more to finish the equation of the line in its standard slope-intercept form:

y=4x-24-2=4x-26

So the equation of the line is:

y=4x-26

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Write the equation whose roots are 6 and 1, and whose leading coefficient is 4.
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Answer:

4(x-6)(x-1) = 0

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Step-by-step explanation:

First, let's write an equation where the roots are 6 and 1.

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We can therefore plug what we know into this equation:

4(x-6)(x-1) = 0

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