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3 years ago

6

Helen got a $7 reduction in the price of a pair of jeans that are normally $32. What is the approximate percent decrease in the

price?
The percent decrease is 15%.
The percent decrease is 21%.
The percent decrease is 43%.
The percent decrease is 78%

2 answers:

Mila [183]3 years ago

6 0

I believe it is 21% decrease sorry if it’s not

Yuliya22 [10]3 years ago

3 0

Answer:

Step-by-step explanation:

it is 21%

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Find the measure <br>someone please help

Ierofanga [76]

Answer:

m∠B = 31°

Step-by-step explanation:

First, find the measure of angle ACB by subtracting its supplement from 180 degrees:

180 - 113 = 77

m∠ACB = 77°

Then subtract both m∠A and m∠ACB from 180 degrees, since the interior angles of a triangle always add to 180°:

m∠B = 180° - 72° - 77°

m∠B = 31°

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2 years ago

What relationship exists between N and K? Given: KLMN is a parallelogram.

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3 years ago

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The average gasoline price of one of the major oil companies in Europe has been $1.25 per liter. Recently, the company has under

Ann [662]

Answer:

$t=\frac{1.20-1.25}{\frac{0.14}{\sqrt{49}}}=-2.50$

Step-by-step explanation:

Data given and notation

$\bar X=1.20$ represent the sample mean given

$\sigma = 0.14$ represent the population standard deviation

$n=49$ sample size

$\mu_o =1.25$ represent the value that we want to test

t would represent the statistic (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean for the gasoline prices is lower than 1.25, the system of hypothesis would be:

Null hypothesis: $\mu \geq 1.25$

Alternative hypothesis: $\mu < 1.25$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{1.20-1.25}{\frac{0.14}{\sqrt{49}}}=-2.50$

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3 years ago

According to a study conducted by the Gallup Organization, the the proportion of Americans who are afraid to fly is 0.10. A rand

notsponge [240]

Answer: 0.1457

Step-by-step explanation:

Let p be the population proportion.

Given: The proportion of Americans who are afraid to fly is 0.10.

i.e. p= 0.10

Sample size : n= 1100

Sample proportion of Americans who are afraid to fly = $\hat{p}=\dfrac{121}{1100}=0.11$

We assume that the population is normally distributed

Now, the probability that the sample proportion is more than 0.11:

$P(\hat{p}>0.11)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.11-0.10}{\sqrt{\dfrac{0.10(0.90)}{1100}}})\\\\=P(z>\dfrac{0.01}{0.0090453})\ \ \ [\because z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}} ]\\\\=P(z>1.1055)\\\\=1-P(z\leq1.055)\\\\=1-0.8543=0.1457\ \ \ [\text{using z-table}]$

Hence, the probability that the sample proportion is more than 0.11 = 0.1457

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2 years ago

For questions 1-4 The spinner to the left is spun 100 times.

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Answer:

1) If it is spun 250 times, it will not land on W 207 times.

2) If it is spun 100 times, it will land on N 17 times (rounded up).

3) 1 out of 6

4) It has the same answer as 1) <em>(If it is spun 250 times, it will not land on W 207 times.)</em>

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2 years ago