-64, -50, -45, 28, 34, 65
Juan's least integer scores in both tests will be 85 and 100 respectively.
- Test average of his two scores is atleast 92
Let :
- Score on test 1 = b
- Score on test 2 = b + 15
Average score can be related thus:
- (Sum of score ÷ number of test) ≥ 92
- (b + b + 15) ÷ 2 ≥ 92
- (2b + 15) ÷ 2 = 92
- 2b + 15 = 184
- 2b = 184 - 15
- 2b = 169
- b = 169 ÷ 2
- b = 84.5
Therefore, since both scores are integers, his least scores on both tests will be ::
Learn more :brainly.com/question/15528814
Answer:
Because the number would be multiplied by an even number, which is 2. If the number (odd or even) is multiplied by two, then the result would be an <em>even number</em>.
Proof:
2(1) = 2
2(6) = 12
2(7) = 14
2(3) = 6
The number would then be added by an odd number, which is 1. If an even number is added with an odd number, then the result would be an odd number.
Proof:
2 + 1 = 3
12 + 1 = 13
14 + 1 = 15
6 + 1 = 7
Answer:
304m^2
Step-by-step explanation:
First find the surface area of the base by multiplying the length by the width.
(12m) (8m)= 96m^2
Second, find the surface area of the front and back triangles using the formula <em>1/2 (base) (height)</em>. Use the length for the base.
1/2 (12m) (10m)= 60m^2
Next, find the surface area of the side triangles using the formula <em>1/2 (base) (height). </em>Use the width as the base.
1/2 (8m) (11m)= 44m^2
Last, add the surface area of each section. Make sure you add the area of each face.(we only solved for 1 of the front/ back triangles and 1 of the side triangles) To make it easier to understand I wrote out an equation to show how I added the surface areas.
base=a, front/ back triangles= b, side triangles=c
SA= a + 2b +2c or SA= a +b +b +c +c
Using one of the equations above solve for the total surface area.
SA= (96m^2) + (60m^2) +(60m^2) +(44m^2) +(44m^2)
or
SA= (96m^2) + 2(60m^2) +2(44m^2)
SA= (96m^2) +(120m^2) +(88m^2)
SA= 304m^2
