Question

A lab group wishes to determine the volume of some zinc beads. They fill a graduated cylinder to the 42.55-mL mark with water. They carefully add the beads to the cylinder. The water level rises to 76.85 mL. What value should they report as the volume of the zinc beads?​

Answer 1

 34.30 mL will be The volume of the zinc beads

The principle is  that a floating or sinking object, liquid will always be displaced and volume of displaced liquid is equal to the volume of object.

So, the volume of the solid object is calculated as the differences between the final and the initial cylinder readings.

Vsolid = ΔV = V2 – V1.

V1 is the volume of the liquid.

V2 is the sum of the volume of the liquid and the solid object

Notice that V2 is greater than V1

Here  initial reading=V1 = 42.55 mL,         final reading=V2 = 76.85 mL

The volume of the solid object is

Volume of zinc beads = 76.85 - 42.55 = 34.30 mL

This is because the volume of the liquid and the volume of the solid object are additive.  

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Answer 2

The volume of the zinc beads will be 34.30 mL

The principle is such that a floating or sinking liquid will always displace its volume in any liquid.

As we know that floating or sinking liquid will always displace its volume in any liquid. So, the volume of the solid is calculated as the differences between the final and the initial cylinder readings.

Here  initial reading = 42.55 mL,

         final reading = 76.85 mL

Volume of zinc beads = 76.85 - 42.55

                                    = 34.30 mL

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