M=d/f so,
f=d/M
f=25/.01. =2500cm
The critical value of r is mathematically given as r = +0.487, with no significant linear correlation. Option A.
<h3>What are the critical values of r?</h3>
Question Parameters
r = -0.868
n = 5
df = 5 - 2
df = 3
Critical values 
Generally, there exists no linear correlation between the Critical values
as r=0.878
In conclusion, Critical values: r = +0.487, no significant linear correlation
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Answer:
415
Step-by-step explanation:
the nth term of the sequence is -13 + 4n
the sequence is an arithmetic progression with nth term a + (n - 1)d
a = -9, d = a5- a4 = 7 -3 =4
nth = -9 + (n -1) 4
= -9 + 4n -4
= -13 + 4n
hence the 107th term; -13 + 4*107
-13 + 428 = 415
The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b...
<span>the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. </span>
<span>2cosθ = 1 => θ = ±π/3 </span>
<span>A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ </span>
<span>= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ </span>
<span>= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. </span>
<span>.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] </span>
<span>= 3θ/2 +sin(2θ) - sin(θ) </span>
<span>Area = A(π/3) - A(-π/3) </span>
<span>= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) </span>
<span>= π.</span>
