All categories

3 years ago

Determine the sign of cos pi divided by seven without using a calculator.

Mathematics

2 answers:

Sophie [7]3 years ago

3 0

The angle $\frac{\pi}{7}$ is in Quadrant 1 and cos of an angle in quadrant 1 is always positive

Aliun [14]3 years ago

3 0

Answer:

The $\cos \frac{\pi}{7}$ has positive sign.

Step-by-step explanation:

we need to determine the sign of $\cos \frac{\pi}{7}$ without using calculator

Cartesian system ( shown in figure -1)

The angle $\cos \frac{\pi}{7}$ lies in quadrant-1 , Where angles are zero (0) to $\frac{\pi}{2}$

and in first quadrant all trigonometric ratios has positive sign

so, $\cos \frac{\pi}{7}$ has positive sign.

You might be interested in

On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (negative 2, 3) an

Firlakuza [10]

Answer:

C on edge

Step-by-step explanation:

9 0

2 years ago

Read 2 more answers

Para pertenecer al equipo de futbol femenino de una ciudad se deben presentar 18 pruebas y por cada prueba hecha de forma correc

GenaCL600 [577]

Answer:

150 scores

Step-by-step explanation:

The computation of the score did she get is shown below:

Since there is 18 test presented

And if the test is done on correct manner so 10 points should be awarded

Now since fifth-sixth would be done correctly

So,

= 18 × 5 ÷ 6 × 10

= 150 scores

7 0

2 years ago

If n is at least 8, which inequality best represents the values of n? n > 8 n ≥ 8 n < 8 n ≤ 8

strojnjashka [21]

N>8 but with the little line underneath.
So choice two

4 0

3 years ago

Read 2 more answers

How to solve this derivative. f(x)={ln(3x)}^2x with steps...

AysviL [449]

Rewrite f(x) as a nested exponential-logarithm expression :

$\left(\ln(3x)\right)^{2x} = \exp\left(\ln\left(\ln(3x)\right)^{2x}\right)$

(where $\exp(x) = e^x$ )

One of the properties of logarithms lets us drop the exponent as a coefficient:

$\exp\left(\ln\left(\ln(3x)\right)^{2x}\right) = \exp\left(2x\ln\left(\ln(3x)\right)\right)$

Now, by the chain rule, we have

$f(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \implies \\\\ f'(x) = \left(\exp\left(2x\ln\left(\ln(3x)\right)\right)\right)' \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2x\ln\left(\ln(3x)\right)\right)'$

By the product rule,

$f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left( (2x)' \ln\left(\ln(3x)\right) + 2x\left(\ln\left(\ln(3x)\right)\right)' \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left( 2\ln\left(\ln(3x)\right) + 2x\left(\ln\left(\ln(3x)\right)\right)' \right)$

By the chain rule again,

$f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + 2x \cdot \dfrac1{\ln(3x)} \cdot \left(\ln(3x)\right)' \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + \dfrac{2x}{\ln(3x)} \cdot \dfrac1{3x} \cdot (3x)' \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + \dfrac{2}{3\ln(3x)} \cdot 3 \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + \dfrac{2}{\ln(3x)} \right)$

Then simplify this to

$f'(x) = \boxed{\left(\ln(3x)\right)^{2x} \left(2\ln\left(\ln(3x)\right) + \dfrac{2}{\ln(3x)} \right)}$

8 0

2 years ago

#2 which table describes a function ??

Ludmilka [50]

Answer:

Step-by-step explanation:

A function can only have one y-output per x-input (However, it is ok for one y-output to have multiple x-inputs). The only table that doesn't contain two y-outputs for one x-input is H.

4 0

3 years ago