Answer:
Shift 2 unit left
Flip the graph about y-axis
Stretch horizontally by factor 2
Shift vertically up by 2 units
Step-by-step explanation:
Given:
Parent function: 
Transformation function: 
Take -2 common from transform function f(x)
![f(x)=\log[-2(x+2)]+2](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-2%28x%2B2%29%5D%2B2)
Now we see the step-by-step translation

Shift 2 unit left ( x → x+2 )

Flip the graph about y-axis ( (x+2) → - (x+2) )
![f(x)=\log[-(x+2)]](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-%28x%2B2%29%5D)
Stretch horizontally by factor 2 [ -x(x+2) → -2(x+2) ]
![f(x)=\log[-2(x+2)]](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-2%28x%2B2%29%5D)
Shift vertically up by 2 units [ f(x) → f(x) + 2 ]
![f(x)=\log[-2(x+2)]+2](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-2%28x%2B2%29%5D%2B2)
Simplify the function:

Hence, Using four step of transformation to get new function 
Answer:

Step-by-step explanation:
When subtracting polynomials, first start with distributing the negative sign to the second polynomial:

Simplify by combining like terms:

Answer:
Step-by-step segment dc bisects segment ab, then point d is equidistant from points a and b because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects. if segment dc bisects segment ab, then point d is equidistant from points a and b because congruent parts of congruent triangles are congruent. if segment ad bisects segment ab, then point d is equidistant from points a and b because a point on a perpendicular bisector is equidistant from:
Answer:
(HA, HB, HC, HD, TA, TB, TC, TD)
Step-by-step explanation:
Spinner : (a, b, c. d)
Coin : (H, T)
Sample space :
____ A _____ B ______ C ______ D
H __HA ____ HB _____ HC _____ HD
_
T__TA _____TB ______ TC _____ TD
Sample space : (HA, HB, HC, HD, TA, TB, TC, TD)
Answer: Rotation, Translation and Reflection
Explanation
Rotation, translation and reflection moves the shape, resulting in a congruent shape but in a different position. Dilation changes the length/width of the shape. The shape can be similar, but not congruent.