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Ugo [173]
1 year ago
7

The steps for inscribing a circle in a triangle are shown:Step 1Construct the perpendicular bisector of one angle of the triangl

e.Step 2Construct the angle bisector of another angle of the triangle.Step 3Indicate the point of intersection of the bisectors with a point representing the center of the circle.Step 4Construct a perpendicular line from the center to a side of the triangle.Step 5Place the compass on the center, adjust its length to where the perpendicular line intersects a side of the triangle, and draw your inscribed circle.Which step is incorrect, and how can it be fixed?
Mathematics
1 answer:
nevsk [136]1 year ago
6 0

Solution

- The correct steps for drawing a circle in a triangle are given below:

1. Bisect one of the angles

2. Bisect another angle

3. Where they cross is the center of the inscribed circle, called the incenter

4. Construct a perpendicular from the center point to one side of the triangle

5. Place compass on the center point, adjust its length to where the perpendicular crosses the triangle, and draw your inscribed circle!

- Based on these steps above and comparing them with the steps given in the question, every step given in the question is correct except Step 1.

- Step 1 given in the question, says we should construct a perpendicular bisector of one angle in the triangle. This is not correct because of the use of perpendicular bisector. This is only used for bisecting lines, not angles.

Final Answer

The answer is Step 1

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Answer:

0 < x ≤ 100 and 0 < y ≤ 300

Step-by-step explanation:

THIS IS THE COMPLETE QUESTION BELOW;

college is currently accepting students that are both in-state and out-of-state. They plan to accept three times as many in-state students as out-of-state, and they only have space to accept 100 out-of-state students. Let x = the number of out-of-state students and y = the number in-state students. Write the constraints to represent the incoming students at the college.

0 < x ≤ 100 and 0 < y ≤ 300

x > 0 and y > 0

0 < x ≤ 100 and y > 300

0 < x and y < 100

SOLUTION

they only have space to accept 100 out-of-state students,which means that the Maximum number of out-of-state students that can be accepted is 100

Then x= 100(Maximum number of out-of-state students that can be accepted)

They plan to accept three times as many in-state students as out-of-state which means that

Y = 3x(Maximum number of in-state students)

Then we can deduced that the numbee out-of-state students that can be accepted can lyes between the range of 0 and 100 which means from interval 0 to 100

Which can be written as 0 < x ≤ 100

But we need to know the interval for the Maximum number of in-state students(Y), to do that we need to multiply the equation above by 3 since Y = 3x

0 < x ≤ 100

3× 0 = 0

3× X = X

3× 100= 300

Then 0 < 3x≤ 300

But we know that Y = 3x then substitute into last equation

We have

0 < y ≤ 300

ThenBthe constraints to represent the incoming students at the college is

0 < x ≤ 100 and 0 < y ≤ 300

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