A bag contains four red marbles, two Yellow Marbles and five blue marbles.
Two marbles are drawn at random without replacement.
Total number of marbles are,

There are 11 ways to select first marble and 10 ways to select second marble.
The total number of possible outcomes are calculated as,

Thus the total number of possible outcomes are 110.
Steps to solve:
2(n + 3) = 2n + 3
~Distribute left side
2n + 6 = 2n + 3
~Subtract 6 to both sides
2n = 2n - 3
~Subtract 2n to both sides
n = -3
Best of Luck!
Answer: 2(x^2+1)^3 (-8x^4-16x^2+x-8)
Step-by-step explanation:
Answer:
5/32
Step-by-step explanation:
If a coin if flipped five times with four heads, then it has exactly one tail. The number of way to arrange four heads and one tail are as follows:
T H H H H
H T H H H
H H T H H
H H H T H
H H H H T
Essentially, there are five way because there are five "positions" where the tail could be.
Then, you need to find the total amount of possibilities for flipping a coin five times. Every time you flip it, there are two possibilities- heads and tails. Therefore, for five flips, the total amount of possibilities is
2x2x2x2x2 = 32
You know that
probability= # of desired outcome
----------------------------------
# of total outcomes
So the probablity is 5/32.
I'd personally go with A and C, The rest don't make too much sense. Don't count on my answer just yet though.