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Ugo [173]
1 year ago
7

The steps for inscribing a circle in a triangle are shown:Step 1Construct the perpendicular bisector of one angle of the triangl

e.Step 2Construct the angle bisector of another angle of the triangle.Step 3Indicate the point of intersection of the bisectors with a point representing the center of the circle.Step 4Construct a perpendicular line from the center to a side of the triangle.Step 5Place the compass on the center, adjust its length to where the perpendicular line intersects a side of the triangle, and draw your inscribed circle.Which step is incorrect, and how can it be fixed?
Mathematics
1 answer:
nevsk [136]1 year ago
6 0

Solution

- The correct steps for drawing a circle in a triangle are given below:

1. Bisect one of the angles

2. Bisect another angle

3. Where they cross is the center of the inscribed circle, called the incenter

4. Construct a perpendicular from the center point to one side of the triangle

5. Place compass on the center point, adjust its length to where the perpendicular crosses the triangle, and draw your inscribed circle!

- Based on these steps above and comparing them with the steps given in the question, every step given in the question is correct except Step 1.

- Step 1 given in the question, says we should construct a perpendicular bisector of one angle in the triangle. This is not correct because of the use of perpendicular bisector. This is only used for bisecting lines, not angles.

Final Answer

The answer is Step 1

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Andrea, Justin, and Virginia went to an office supply store. Andrea bought 6 pencils, 7 markers, and 8 erasers. Her total was $1
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Answer:

x=0.25\,,\,y=1.75\,,\,z=0.25

Step-by-step explanation:

Let x,y,z denotes number of pencils, markers, erasers respectively.

For Andrea:

6x+7y+8z=15.75\,\,\,(i)

For Justin:

6x+8y+5z=16.75\,\,\,(ii)

For Virginia:

5x+5y+7z=11.75\,\,\,(iii)

On subtracting equations (i) and (ii), we get

(6x+7y+8z)-(6x+8y+5z)=15.75-16.75\\-y+3z=-1\\y-3z=1\\y=1+3z

Put y=1+3z in equation (i)

6x+7(1+3z)+8z=15.75\\6x+29z=8.75\,\,\,(iv)

Put y=1+3z in equation (iii)

5x+5(1+3z)+7z=11.75\\5x+22z=6.75\,\,\,(v)

Multiply equation (iv) by 5 and equation (v) by 6 and then subtract both the equations.

5(6x+29z)-6(5x+22z)=5(8.75)-6(6.75)\\13z=3.25\\z=\frac{3.25}{13}=0.25

Put z=0.25 in equation y=1+3z

y=1+3(0.25)=1.75

Put y=1.75\,,\,z=0.25 in equation (i)

6x+7(1.75)+8(0.25)=15.75\\6x+12.25+2=15.75\\6x=1.5\\x=0.25

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4 years ago
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