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liberstina [14]
1 year ago
8

List and describe with details at least three approaches to selecting processes from priority-based multi-level queues.

Computers and Technology
1 answer:
garik1379 [7]1 year ago
6 0

Based on the information given, it is important to give higher priority to the queue that contains the high priority thread.

<h3></h3><h3>What is the Important Fact?</h3>
  • A lot of interrupts can take place at any time, and due to that, they cannot always be ignored as  the part of code affected by interrupts need to be guarded from constant use.
  • So, the load-balancing requirements for keeping about the same number of threads would need to be taken or retained and the important case of top priority thread would also be kept.
  • An  priority-based scheduling algorithm can handle this situation if one run queue had all high-priority threads and a second queue had all low-priority threads because if giving greater priority to the two queue that has the national priority comment section as well as, so, first method is the thread in all of the queue.
  • Multi-level queue scheduling algorithm is used in scenarios where the processes can be classified into groups based on property like process type, CPU time, IO access, memory size, etc. One general classification of the processes is foreground processes and background processes.

To learn more about multi-level refer to:

brainly.com/question/16902508

#SPJ4

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2 years ago
Read the following scenario:
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4 years ago
What is the decimal format of the binary IP address 11001110.00111010.10101010.01000011?
Neporo4naja [7]

Answer:

206.58.170.67 is the decimal format of the given binary IP address.

Explanation:

we can convert the binary number into decimal by the following procedure.

11001110 = 1x2⁷+1x2⁶+0x2⁵+0x2⁴+1x2³+1x2²+1x2¹+0x2⁰

            = 128 + 64 + 0 + 0 + 8 + 4 + 2 + 0

            =   206

00111010 = 0x2⁷+0x2⁶+1x2⁵+ 1x2⁴+1x2³+0x2²+1x2¹+0x2⁰

               = 0 + 0 + 32 + 16 + 8 + 0 + 2 + 0

               = 58

10101010 = 1x2⁷+0x2⁶+1x2⁵+ 0x2⁴+1x2³+0x2²+1x2¹+0x2⁰

              = 128 + 0 + 32 + 0 + 8 + 0 + 2 + 0

              = 170

01000011 =  0x2⁷+ 1x2⁶+ 0x2⁵+ 0x2⁴+ 0x2³+0x2²+1x2¹+1x2⁰

                = 0 + 64 + 0 + 0 + 0 + 0 + 2 + 1

                =  67

so, the IP address is becomes 206.58.170.67

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