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liberstina [14]
1 year ago
8

List and describe with details at least three approaches to selecting processes from priority-based multi-level queues.

Computers and Technology
1 answer:
garik1379 [7]1 year ago
6 0

Based on the information given, it is important to give higher priority to the queue that contains the high priority thread.

<h3></h3><h3>What is the Important Fact?</h3>
  • A lot of interrupts can take place at any time, and due to that, they cannot always be ignored as  the part of code affected by interrupts need to be guarded from constant use.
  • So, the load-balancing requirements for keeping about the same number of threads would need to be taken or retained and the important case of top priority thread would also be kept.
  • An  priority-based scheduling algorithm can handle this situation if one run queue had all high-priority threads and a second queue had all low-priority threads because if giving greater priority to the two queue that has the national priority comment section as well as, so, first method is the thread in all of the queue.
  • Multi-level queue scheduling algorithm is used in scenarios where the processes can be classified into groups based on property like process type, CPU time, IO access, memory size, etc. One general classification of the processes is foreground processes and background processes.

To learn more about multi-level refer to:

brainly.com/question/16902508

#SPJ4

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Explanation:

Argon atom has atomic number 18. Then, it has 18 protons and 18 electrons.

To determine the quantum numbers you must do the electron configuration.

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The last electron is in the 3p orbital.

The quantum numbers associated with the 3p orbitals are:

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  • l = 1 (orbitals s correspond to l = 0, orbitals p correspond to l  = 1, orbitals d, correspond to l  = 2 , and orbitals f correspond to  l = 3)

  • m_l can be -1, 0, or 1 (from - l  to + l )

  • the fourth quantum number, the spin can be +1/2 or -1/2

Thus, the six possibilities for the last six electrons are:

  • (3, 1, -1 +1/2)
  • (3, 1, -1, -1/2)
  • (3, 1, 0, +1/2)
  • (3, 1, 0, -1/2)
  • (3, 1, 1, +1/2)
  • (3, 1, 1, -1/2)

Hence, the correct choice is:

  • n = 3
  • l  = 1
  • m_l = 1
  • m_s=+1/2
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