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4 years ago

PLEASE HELP WITH THESE TWO QUESTIONSSS 1. Which value is equivalent to sin20∘?

Mathematics

1 answer:

Nata [24]4 years ago

4 0

Answer:

a) $\cos(70\degree)$

b) 12.72 units

Step-by-step explanation:

Recall that the sine and cosine are completed functions.

This means that: $\sin(x)=\cos(90-x)$

$\sin(20\degree)=\cos(90-20)$

$\sin(20\degree)=\cos(70\degree)$

Recall that: sine ratio is opposite/hypotenuse

$\sin 58=\frac{|PQ|}{15}$

This implies that:

$|PQ|=15\sin 58$

$|PQ|=15(0.848)$

$|PQ|=12.72$

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What is the product of 3x+4 and 6x^{2} −5x+7?

LUCKY_DIMON [66]

$(3x + 4)(6 {x}^{2} - 5x + 7) \\ = 18 {x}^{3} - 15 {x}^{2} + 21x + 24 {x}^{2} - 20x + 28 \\ = 18 {x}^{3} + 9 {x}^{2} + x + 28$

I hope I helped you^_^

8 0

3 years ago

My am never friends have 3/4 and one nickel to spend if Maia and her friends share the money equally how much for each person ge

EleoNora [17]

Answer:

Each person get = 20 cents

Step-by-step explanation:

Given - Maya and three friends have three quarters and one nickel to spend.

To find - If Maya and her friends share the money equally how much will each person get ?

Proof -

We know that

1 nickel = 5 cents

1 quarter = 25 cents

As they spent, 3 quarters and one nickel

So,

Total money spent = 3(25) + 5 = 75 + 5 = 80 cents

⇒Total money spent = 80 cents

Now,

Total people = 4 (Maya and three friends )

Now,

Given that, They share the money equally

So,

Each person get = $\frac{80}{4}$ = 20 cents

5 0

3 years ago

A store regularly sold 2 cans of soup for $1.28. It advertised a special sale of 6 cans for $3.12. A customer bought 12 cans at

olga nikolaevna [1]

The customer saved $1.36 over the regular price

5 0

3 years ago

Read 2 more answers

A ball with mass m kg is thrown upward with initial velocity 28 m/s from the roof of a building 17 m high. Neglect air resistanc

Nutka1998 [239]

a. At its maximum height, the ball has zero vertical velocity, so

$-\left(28\dfrac{\rm m}{\rm s}\right)^2=2(-g)(y_{\rm max}-17\,\mathrm m)$

$\implies y_{\rm max}=57\,\mathrm m$

b. The ball's height in the air $y$ at time $t$ is given according to

$y=17\,\mathrm m+\left(28\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2$

Solve for $t$ when $y=0$ :

$17+28t-4.9t^2=0\implies t\approx6.3\,\mathrm s$

3 0

3 years ago

A simple random sample from a population with a normal distribution of 99 body temperatures has xbar = 99.10°F and s = 0.64°F. C

motikmotik

The general formula for the margin of error is e = (zs)/√n, when the sample size is 30 or more (otherwise, we'd need to to a t-interval).

Since we're needing a 99% confidence interval, we need to know what the positive z-score associated with this two-tailed area under the normal curve is. This can be a little tricky if you're using a standard normal table. What you want is a two-tailed interval that has an area of .99. What this means is that the remaining 0.01 is divided into 0.005 on each end. This then means that, to the right of the mean (which is 0), the area is 0.005 less than the total right-half area of 0.5, or 0.495. The total cumulative area, then, includes this plus the left half of .5, or 0.5 + 0.495 = .0995.

Then, if all we have to go on is a cumulative standard normal table, then we need to find the area closest to 0.995 and find the corresponding z-score. This z-score is 2.58.

Now that we have the z-score, we can now plug in all the values into the formula.

e = (2.58 · 0.66)/√102 = 0.1686.

So the 99% confidence interval will be that far above and below the mean (which is 98.8). So the lower limit is 98.8 - 0.1686 = 98.631, and the upper limit is 98.8 + 0.1686 = 98.967.

The TI-84 method:

This is much easier, if you're allowed to use this technology. You begin with the STAT button, and then move over to the TESTS menu. Then select ZInterval. We have summary stats rather than data in this problem, so we select Stats as the input. For the standard deviation, we put 0.66, for x-bar 98.8, for n 102, and for C-level 0.99. Then select Calculate, and it will provide the interval at the top of the screen (98.632, 98.968). Note that the lower limit is slightly different by this method. This is because, when doing it by hand, we had to approximate the z-score. This created a rounding error, albeit a small one.

4 0

3 years ago