The right thing to do is to PASS BY THE BUOY WHILE KEEPING IT ON YOUR RIGHT HAND SIDE. Buoy is an example of aids to navigation. In the United States, the lateral system is used, which involves marking the sides of the channels. When a vessel enter a smaller body of water from a large one, that means the vessel is returning, it is expected that the vessel leave the red buoy to starboard when returning.
OK, this is pretty interesting.
First get out your parameters.
Pressure of gas, P= 1.5×10^5 Pa
Initial volume, V1=0.0002m³
Final volume, V2=0.0006m³
Heat change, ∆H= +32J (it is positive since it was absorbed.)
Now you can solve.
∆U= ∆H—P∆V
∆U=32J—(1.5×10^5×(0.0006—0.0002))
∆U=32J—(1.5×10^5×0.0004)
∆U=32J—(1.5×10^5×4×10^—4)
∆U=32—60
∆U=—28J
That corresponds to option C.
Answer:
F₁ = F₂
Explanation:
Given that
floor pushing up on you by force F₁
gravity pulling down by force F₂
From second law of Newton's
F₁ - F₂ = m a
But here given that ,elevator is moving with constant speed .It means that acceleration of the elevator is zero.
a= 0 m/s²
F₁ - F₂ = m x 0
F₁ = F₂
<span>The most likely solution would be to check the commutator because the current is not reversing.</span>