Question

Fluid flows at 2.0 m/s through a pipe of diameter 3.0 cm. What is the volume flow rate of the fluid in m^3/

Answer 1

Answer:

Volume flow rate = $1.41 \times 10^{-3}m^3/s$

Explanation:

The volume flow rate through a channel can be gotten by multiplying its area and its velocity.

The channel under consideration is a circular channel. Hence, the cross-sectional area can be calculated by using the relation for calculating the area of a circle

Cross-sectional area = $\pi \times d^{2}/4$

$A = \pi \times (3\times 10^-2)^2 /4 = 7.07 \times 10 ^-4 m^2$

volume flow rate= $A = 7.07 \times 10 ^-4 m^2 X 2.0 = 1.41 \times 10^{-3}m^3/s$

Volume flow rate = $1.41 \times 10^{-3}m^3/s$