All categories

4 years ago

Fluid flows at 2.0 m/s through a pipe of diameter 3.0 cm. What is the volume flow rate of the fluid in m^3/

Physics

1 answer:

fenix001 [56]4 years ago

7 0

Answer:

Volume flow rate = $1.41 \times 10^{-3}m^3/s$

Explanation:

The volume flow rate through a channel can be gotten by multiplying its area and its velocity.

The channel under consideration is a circular channel. Hence, the cross-sectional area can be calculated by using the relation for calculating the area of a circle

Cross-sectional area = $\pi \times d^{2}/4$

$A = \pi \times (3\times 10^-2)^2 /4 = 7.07 \times 10 ^-4 m^2$

volume flow rate= $A = 7.07 \times 10 ^-4 m^2 X 2.0 = 1.41 \times 10^{-3}m^3/s$

Volume flow rate = $1.41 \times 10^{-3}m^3/s$

You might be interested in

20. Which statement is false? Rewrite it so that it is true. a. Fusion involves the combination of two smaller atoms into a larg

Annette [7]

Answer:

c. Fission and fusion are two processes that release very little amounts of energy.

Explanation:

This statement is false. In fact, both fission and fusion are processes which release very large amounts of energy. The statement can be rewritten as it is true as follows:

"Fission and fusion are two processes that release very large amounts of energy."

Fission occurs when a large nucleus break apart, splitting into smaller nuclei, while fusion occurs when two light nuclei combine together into a larger nucleus. In both cases, the mass of the reactants is larger than the mass of the final products, so some of the mass has been converted into energy, according to Einstein's equation:

$E = \Delta m c^2$

where

E is the energy released

$\Delta m$ is the mass lost in the process

c is the speed of light

Since c is a very large number ( $c=3\cdot 10^8 m/s$ ), we see that even a very small mass $\Delta m$ causes the released of a huge amount of energy, so both fission and fusion release large amounts of energy.

3 0

4 years ago

A child is swinging back and forth on a swing. Changes in her kinetic and potential energy are happening each moment. At which p

mina [271]

Answer:

When the person has swung all the way back (position A), the swing pauses a moment. ... As the swing continues forward, it gradually slows down. Its kinetic energy changes back to potential energy until it reaches the farthest point in its arc (position C).

5 0

3 years ago

A high diver of mass 74.0 kg jumps off a board 9.00 m above the water. If his downward motion is stopped 2.50 seconds after he e

stiv31 [10]

Answer:

1120 N

Explanation:

The velocity with which he hits the water can be found with kinematics:

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (-9.8 m/s²) (-9.00 m)

v = -13.3 m/s

Or it can be found with conservation of energy.

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × -9.8 m/s² × -9.00 m)

v = -13.3 m/s

Sum of forces on the diver after he hits the water:

∑F = ma

F − mg = m Δv/Δt

F − (74.0 kg) (9.8 m/s²) = (74.0 kg) (0 m/s − (-13.3 m/s)) / (2.50 s)

F = 1120 N

6 0

3 years ago

What is the magnitude of the sum of the two vectors A = 36 units at 53 degrees, and B =47 units at 157 degrees.

Thepotemich [5.8K]

Answer:

51.82

Explanation:

First of all, let's convert both vectors to cartesian coordinates:

Va = 36 < 53° = (36*cos(53), 36*sin(53))

Va = (21.67, 28.75)

Vb = 47 < 157° = (47*cos(157), 47*sin(157))

Vb = (-43.26, 18.36)

The sum of both vectors will be:

Va+Vb = (-21.59, 47.11) Now we will calculate the module of this vector:

$|Va+Vb| = \sqrt{(-21.59)^2+(47.11)^2}=51.82$

4 0

4 years ago

Please help me find the correct words that go with the definition due TONIGHT!!!

umka21 [38]

I sorry but I don’t know if you are doing virtual just keep trying and never give up

5 0

3 years ago