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topjm [15]
3 years ago
9

Stand next to a wall that travels at 30 km/s relative to the Sun. With your feet on the ground, you also travel at the same 30 k

m/s. Do you maintain this speed when your feet leave the ground? What concept supports your answer?
Physics
1 answer:
mars1129 [50]3 years ago
8 0

Answer:

Yes. Inertia keeps the speed maintained though my feet leave the ground.

Explanation:

Inertia is the resistance to the change in position of any object this means this resistance will keep me traveling at 30 km/s relative to the sun. If the person wants to change the position we apply force to do that because inertia is opposing us to not do that. We are always traveling with 30km/s relative to sun due to inertia.

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7. You start to walk toward the east towards home at a constant speed of 4 km/hr. At the same time, Someone else leaves your hom
amm1812

A) position time graph for both is shown

here one of the graph is of lesser slope which means it is moving with less speed while other have larger slope which shows larger speed

At one point they intersects which is the point where they both will meet

B) Let the two will meet after time "t"

now we can say that

if they both will meet after time "t"

then the total distance moved by you and other person will be same as the distance between you and home

so it is given as

v_1t + v_2t = d

4*t + 28*t = 3.2 km

t = \frac{3.2}{32} = 0.1 hr

so they will meet after t = 6 min

so from position time graph we can see that two will meet after t = 6 min where at this position two graphs will intersect


4 0
3 years ago
How to round numbers and find significant digits in physics?? <br> Simple answer? Please???
Mrrafil [7]

Answer:

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3 0
3 years ago
What is the mass of an object that has a weight of 110N ?
fgiga [73]
  • Weight (W) = 110 N
  • Acceleration due to gravity (g) = 9.8 m/s^2
  • Let the mass of the object be m.
  • By using the formula, W = mg, we get,
  • 110 N = 9.8 m/s^2 × m
  • or, m = 110 N ÷ 9.8 m/s^2
  • or, m = 11.2 Kg

<u>Answer:</u>

<em><u>The </u></em><em><u>mass </u></em><em><u>of </u></em><em><u>the </u></em><em><u>object </u></em><em><u>is </u></em><em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u>2</u></em><em><u> </u></em><em><u>Kg.</u></em>

Hope you could get an idea from here.

Doubt clarification - use comment section.

3 0
2 years ago
What area of science compares and describes quantities and movements of matter and energy?
qaws [65]

Answer:

the answer is physics

4 0
3 years ago
Suppose you need your silicon circuit element to run continuously for 3 minutes before it shuts off long enough to cool back dow
Zigmanuir [339]

The maximum rate at which energy can be added to the circuit element mathematically given as

MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}

<h3>What is the maximum rate at which energy can be added to the circuit element?</h3>

Generally, the equation for P is  mathematically given as

P=\ln s \frac{\Delta T}{\Delta t}

Therefore

Rate\ of\ Change\ of\ Temp =\frac{p}{lnS}

\frac{p}{lnS}=\frac{7.4 \times 10^{-3}}{23 \times 10^{-6} \times 705}

\frac{p}{lnS}=0.456^{\circ \mathrm{c}} / \mathrm{sec}

Max temp Change

MaxT=5.6^{\circ} \mathrm{C}

\text { time }=3 \times 60

t=180s

In conclusion, Max Energy Rate

MER =23 \times 10^{-6} \times \frac{301 \times 5.6}{180}

MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}

Read more about  Energy

brainly.com/question/13439286

#SPJ1

3 0
2 years ago
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